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shusha [124]
3 years ago
15

The gas in a cylinder has a volume of 3 liters at a pressure of 118 kpa. the pressure of the gas is increased to 221 kpa. assumi

ng the temperature remains constant, what would the new volume be?
Chemistry
1 answer:
Soloha48 [4]3 years ago
3 0
Data:
V1 (initial volume) = 3 g/L
P1 (initial pressure) = 118 kPa
V2 (final volume) = ? (g/L)
P2 (final pressure) = 221 kPa

Formula:
P1 * V1 = P2 * V2

Solving:
P1 * V1 = P2 * V2
118 * 3 = 221 * V2
354 = 221 V2
221 V2 = 354
V_{2} = \frac{354}{221}
\boxed{\boxed{V_{2} \approx 1.60\:g/L}}\end{array}}\qquad\quad\checkmark
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