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shusha [124]
4 years ago
15

The gas in a cylinder has a volume of 3 liters at a pressure of 118 kpa. the pressure of the gas is increased to 221 kpa. assumi

ng the temperature remains constant, what would the new volume be?
Chemistry
1 answer:
Soloha48 [4]4 years ago
3 0
Data:
V1 (initial volume) = 3 g/L
P1 (initial pressure) = 118 kPa
V2 (final volume) = ? (g/L)
P2 (final pressure) = 221 kPa

Formula:
P1 * V1 = P2 * V2

Solving:
P1 * V1 = P2 * V2
118 * 3 = 221 * V2
354 = 221 V2
221 V2 = 354
V_{2} = \frac{354}{221}
\boxed{\boxed{V_{2} \approx 1.60\:g/L}}\end{array}}\qquad\quad\checkmark
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What would be the major product if 1,4-dibromo-4-methylpentane was allowed to react with:
Levart [38]

Answer : The correct answer for a) 4-bromo-2-iodo-4-methyl pentane and b)5-bromo-2-ethoxy-2-methyl pentane.

A) Reaction with NaI :

Reaction of alkyl halide with NaI is known as Finkelstein Reaction . The acetone is used as solvent . It involves bimolecular nucleophillic substitution rmechanism (SN²) . There is replecement of one halogen with other occurs .

The incoming Nucleophile(Nu⁻) (halide) attacks on carbon from back side , while the leaving group (halide) leaves the compound from front side , simultaneously. The product so formed have is inverted .(Image)

NaI releases I⁻ ion which act as nucelophile and attacks on C1 carbon and Br⁻ from C1 carbon is released . Out of two bromines at C1 and C4 carbons , C1 is primary carbon which is less sterically hindered while C-4 is tertiary carbon and sterically hindered . So it is easy for incoming Nu⁻ to attack on C1 carbon .So Br⁻ is repleaced by I⁻.

1,4-dibromo-4-methylpentane + NaI → 4-bromo-1-iodo-4-methylpentane

The product formed from reaction between 1,4-dibromo-4-methylpentane and NaI is 4-bromo-1-iodo-4-methylpentane . (Image)

B) Reaction with AgNO3 :

Reaction of alkyl halide with AgNO3 in ethanol takes place via SN¹ ( unimolecular nucleophilic substitution ) mechanism . In this leaving group(halide) leaves from alkyl halide forming an intermediate carbocation species . The incoming Nu⁻ attack on this carbocation.

AgNO3 reacts releases Ag⁺ion which abstract Br⁻ of C-4 carbon from 1,4-dibromo-4-methylpentane. THis forms tertiary carbocation which is more stable than carbocation formed by removal of Br from C-1 . The ethanol being more Nucleophilic than NO₃⁻ (from AgNO₃), attacks on this carbocation .(Image )

The product formed as a result is 5-bromo-2-ethoxy-2-methyl pentane.

7 0
3 years ago
A plant fertilizer contains 15% by mass nitrogen (N). In a container of soluble plant food, there are 12.2 oz of fertilizer. How
ale4655 [162]
51.86 grams would be in the container.

One ounce is an equivalent of 28.34 grams, so times that by 12.2
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12.2 * 28.34 = 345.75.

Put the percentage into decimal form, so 15% would now be 0.15.

0.15 * 345.75 = 51.86.
8 0
3 years ago
Read 2 more answers
What do you understand by valency electron and valency shell?​
jasenka [17]

Answer:

<h2>total no. of electron present in Valency shell is called valency electron </h2><h2>___________________</h2>

<h2>valency shell is that in which last electron is present</h2>

7 0
3 years ago
For the following species, draw a Lewis structure for one important resonance form. Include all lone pair electrons and assign f
Gemiola [76]

Answer:

The Lewis structures are shown in the figure

Explanation:

The lewis structure will be drawn using following steps

i) we will calculate the total number of valence electrons in the molecule

ii) will assign one bond (two electrons in between two atoms)

iii) then distribute the rest of the valence electrons as lone pair or shared pair based on completion of octet.

The structure of each molecule is given in the figure.

Valence electrons:

NO_{2}^{+}

V.E = 5 +(2)6-1=16

NO_{2}F

V.E =5 +(2)6+7=24

6 0
3 years ago
If the take off velocity of an airplane on a runway is 300 km /hr with an acceleration of 1 m/s2. What is the take off time of t
Rama09 [41]
<h3>Answer:</h3>

83.33 seconds.

<h3>Explanation:</h3>

<u>We are given;</u>

  • Take off velocity as 300 km/hr
  • Acceleration as 1 m/s²

We are required to calculate the take off time of the airplane.

<h3>Step 1: Convert velocity from km/hr to m/s </h3>

We are going to use the conversion factor.

The conversion factor is 3.6 km/hr per m/s

Therefore;

Velocity = 300 km/hr ÷ 3.6 km/hr per m/s

             = 83.33 m/s

<h3>Step 2: Calculate the take off time</h3>

We know that;

v = u + at

where, u is the initial velocity, v the final velocity, a the acceleration and t is time.

But, initial velocity is Zero

Therefore;

83.33 m/s = 1 m/s² × t

Thus;

time = 83.33 m/s ÷ 1 m/s²

       = 83.33 seconds

Therefore, the take off time is 83.33 seconds.

5 0
3 years ago
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