C) During the radioactive decay, alpha particles are released. These positive particles are attracted to the negative plate in the electric field
Explanation:
In nuclear reactions, it should be known that the mass and atomic numbers are usually conserved.
²³⁸₉₂U → ²³⁴₉₀Th + ⁿₐX
This implies that:
238 = 234 + n
92 = 90 + a
When this is true, then the nuclear reaction is balanced. Both atomic and mass numbers can be said to be conserved.
Solving for n and a
n = 4
a = 2
Therefore
²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He
The particle resulting from the decay is an alpha particle. Alpha particles resembles a Helium atom.
Alpha particles are positively charged and they are attracted to the negative plate in the electric field.
Learn more:
Radioactive decay brainly.com/question/10125168
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