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3 years ago

23892U → 23490Th

1 answer:

7 0

C) During the radioactive decay, alpha particles are released. These positive particles are attracted to the negative plate in the electric field

Explanation:

In nuclear reactions, it should be known that the mass and atomic numbers are usually conserved.

²³⁸₉₂U → ²³⁴₉₀Th + ⁿₐX

This implies that:

238 = 234 + n

92 = 90 + a

When this is true, then the nuclear reaction is balanced. Both atomic and mass numbers can be said to be conserved.

Solving for n and a

n = 4

a = 2

Therefore

²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He

The particle resulting from the decay is an alpha particle. Alpha particles resembles a Helium atom.

Alpha particles are positively charged and they are attracted to the negative plate in the electric field.

Learn more:

Radioactive decay brainly.com/question/10125168

#learnwithBrainly

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3 years ago

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3 years ago

A 6.00 g lead bullet traveling at420 m/s is stopped by a large

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Answer:

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Explanation:

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3 years ago

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3 years ago