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Xelga [282]
3 years ago
5

In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. Calculate the ma

gnitude and direction of the net horizontal force on the rope.
Physics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

74 N to the right

Explanation:

the forces are going in opposite horizontal directions, meaning that they are directly opposing each other. this means that you can subtract the force applied in the direction that is greater from the direction that is less to get the net force for the greater direction

this means 182 N - 108 N = 74 N to the right

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egoroff_w [7]

Answer:

3500N

Explanation:

Given parameters:

Mass of driver  = 50kg

Speed  = 35m/s

Time  = 0.5s

Unknown:

Average force the seat belt exerts on her = ?

Solution:

The average force the seat belt exerts on her can be deduced from Newton's second law of motion.

   F = mass x acceleration

So;

     F  = mass x  \frac{change in velocity }{time}

  F  = 50 x \frac{35}{0.5}    = 3500N

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A skydiver has jumped out of a plane and is falling faster and faster. what forces are present in this situation
kompoz [17]
Gravity and air resistance 

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A child accidentally drops a toy from his apartment window. It falls for 1.05 seconds. What is the velocity of the toy just befo
AVprozaik [17]

Sorry!

This cannot be answered. We don't have weight, height, etc.

6 0
3 years ago
Not sure if it went through last time. Please help asap!
Olin [163]
The equation for force is F=ma. Because we have the value of mass (0.42 kg) and the acceleration (14.8 m/s^2), simply plug them into the equation for force to get
0.42 \times 14.8 = 6.22
The answer is 6.22 N because newtons are the unit used to measure force.
8 0
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Explain nanotechnology. Its advantages, disadvantages with examples or application? ​
Volgvan

Answer:

PURPOSE

This information bulletin clarifies the Department of Building and Safety’s (LADBS) requirement

relating to the equipment (product) and wiring approval as delineated in Sections 110.2, 110.3,

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100)

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