Answer:
6 km/h west
Explanation:
During part c of the hike, the hiker moved 6 km west, and the time was 9.45 am to 10.45 am.
So, we have:
- displacement: d = 6 km west
- time taken: from 9.45 am to 10.45 am = 1 hour
Therefore, the average velocity is given by the ratio between displacement and time taken:
and the direction is the same as the displacement (west)
A ladder 25 feet long is leaning against a house. The base of the ladder is pulled away at a rate of 2 ft/sec.
a.) How fast is the top of the ladder moving down the wall when the base of the ladder is 12 feet from the wall?
Answer:
dy/dt = -1.094ft/sec
Explanation:
Given that:
dz/dt = 0,
dx/dt = 2,
dy/dt = ?
Hence, we have the following
Using Pythagoras theorem
We have 25ft as the hypotenuse, y as the opposite or height of wall, and x as the base of the triangle
X² + y² = z²,
12² + y² = 25²,
y² = 25² - 12²
y = √481
Therefore, we have the following:
2x dx/dt + 2y dy/dt,
= 2z dz/dt,
= 12 (2) √481 dy/dt,
= √481 dy/dt = -24,
= dy/dt = -1.094ft/sec
Therefore, final answer is -1.094ft/sec
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Answer:
See explanation
Explanation:
Solution:-
- We will first set a datum as the free surface of water in the pool.
- There is a square window with side length ( L = 8 m ) on the vertical side of the pool.
- The depth of the pool is given to be 54 m. The top of the window is ( d = 43 m ) from the free surface.
- We are to determine the resultant hydro static force acting on the window.
- Hydro static force ( F ) acting on an object of area ( A ) fully immersed in fluid is given by the following relationship as follows:
F = Pc*A
Where,
Pc: The hydrostaic pressure acting on the centroid of the obect.
- The hydrostatic pressure acting on the centroid of the object immersed in any fluid can be expressed by the following defining relationship:
Pc = γ*yc
Where,
γ: The specific weight of the fluid
yc: The vertical distance from free-surface to the centroid.
- Assuming homogeneous distribution of material used for the window of square shape. The centroid coincides with the geometric center of the window which is as a distance ( yc ) from the free-surface:
- Now we can calculate the resultant hydro static force ( F ) acting on the window. The specific gravity of fluid ( water ) is γ = 9.8KN/m^3.
Note: The values given in the posted question seem unreasonable. I have assumed values in order of convenience. However, the procedure of solving the problem remains exactly the same.
Answer:
or
Explanation:
The force in a spring is described as (F) = (k) x (d) with (d) being the displacement, measured in meters. (F) is to come out in Newtons. So (k) is assigned the appropriate unit for that to happen. The two possibilities listed above achieve that.