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ExtremeBDS [4]
3 years ago
11

On the basis, a given figure, calculate rfficiency of the lever. ​

Physics
1 answer:
daser333 [38]3 years ago
4 0

Explanation:

here,load=100N

effort=200N

distance travelled by load=2cm

distance travelled by effort=10cm

Now, output work=L*Ld

=100*2

=200g

Again,

input work =E*Ed

200*10

2000j

again, efficiency = output work/input work*100%

200/2000*100%

=10%

please don't forget to write symbol

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Find the area of rectangle given below​
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6000 cm<em>²</em>

Explanation:

let width of rectangle = x

Using Pythagorean theorem,

x^{2} +<em> 50² = 130²</em>

<em />x^{2}<em> = 130² - 50² </em>

<em />x^{2}<em> = 14400</em>

<em />x <em>= 120 cm</em>

area of rectangle <em>=</em> length x width

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Given two vectors A--&gt; = 4.20 i^+ 7.20 j^ and B--&gt; = 5.70 i^− 2.40 j^ , find the scalar product of the two vectors A--&gt;
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\vec{A}\times \vec{B}=\begin{vmatrix}i&j&k\\4.2&7.2&0\\5.7&-2.4&0\end{vmatrix}

\vec{A}\times \vec{B}=\hat{k}(-10.08-41.04)=-51.12\hatk}\hat{k}

Angle between two vectors is given by

sin\theta=\frac{\mid a\times b\mid}{\mid a\mid \mi b\mid}

Where \theta in degrees

\mid{\vec{A}}\mid=\sqrt{(4.2)^2+(7.2)^2}=8.3

Using formula\mid a\mid=\sqrt{x^2+y^2}

Where x= Coefficient of unit vector i

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\mid{\vec{B}}\mid=\sqrt{5.7)^2+(-2.4)^2}=6.2

\mid{\vec{A}\times \vec{B}}\mid=\sqrt{(-51.12)^2}=51.12

Using the formula

sin\theta=\frac{51.12}{8.3\times 6.2}=0.993

\theta=sin^{-1}(0.993)=83.2degrees

Hence, the angle between given two vectors=83.2^{\circ}

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