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Iteru [2.4K]
3 years ago
9

the volume of a rectangular solid is the product of its length, width, and height. Calculate the volume of a rectangular solid w

ith length 11.4 cm, width 12.3 cm, and height 3.8 cm.
Chemistry
2 answers:
nalin [4]3 years ago
5 0
12.3*3.8=46.74cm2
46.74*11.4=532.836cm3

RideAnS [48]3 years ago
5 0

Answer: 532.836 cubic centimeters

Explanation:

Given : The volume of a rectangular solid is the product of its length, width, and height.

Then, the  volume of a rectangular solid with length 11.4 cm, width 12.3 cm, and height 3.8 cm will be :-

\text{Volume}=11.4\times12.3\times3.8

Simplify ,

\Rightarrow\ \text{Volume}=532.836\ cm^3

Hence, the volume of the given rectangular prism = 532.836 cubic centimeters

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If it takes 54ml of 0.1 m naoh to neutralize 125 ml of a hcl solution with unknown concentration, what is the concentration of t
dangina [55]
The balanced equation for the reaction between NaOH and HCl is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
number of NaOH moles reacted - 0.1 mol/L x 0.054 L = 0.0054 mol
number of HCl moles reacted = number of NaOH moles reacted 
since the molar ratio of acid to base is 1:1
therefore number of HCl moles reacted - 0.0054 mol
the number of moles of HCl in 125 mL - 0.0054 mol
therefore number of HCl moles in 1000 mL - 0.0054 mol / 125 mL x 1000 mL 
number of moles of solute in 1000 mL is known as the molarity concentration 
concentration of HCl is 0.0432 M
5 0
4 years ago
For the reaction: CH3NH2(aq) + H2O(aq) ⇌ CH3NH3 +(aq) + OH- Determine the change in the pH (ΔpH) for the addition of 6.7 M CH3NH
Korolek [52]

Answer:

The change in the pH (ΔpH) is 2,17

Explanation:

The reaction:

CH₃NH₂(aq) + H₂O(aq) ⇌ CH₃NH₃⁺(aq) + OH⁻

kb = \frac{[OH^{-}][CH_{3}NH_{3}^+]}{[CH_{3}NH_{2}]} <em>(1)</em>

In equilibrium, a solution of CH₃NH₂ 4,7M produces:

[CH₃NH₂] = 4,7 - x

[CH₃NH₃⁺] = x

[OH⁻] = x

Replacing in (1):

4,38x10^{-4} = \frac{x^2}{4,7-x}

x² + 4,38x10⁻⁴x - 2,0586x10⁻³ = 0

The solutions are:

x = -0,0456 No physical sense. There are not negative concentrations.

x = 0,04515 Real answer.

The concentration of [OH⁻] is 0,04515 M.

As pOH = -log [OH⁻] And pH+pOH = 14. The pH of this solution is:

<em>pH = 12,65</em>

The addition of 6,7M produce this changes in concentrations:

[CH₃NH₂] = 4,656 + x

[CH₃NH₃⁺] = 6,74515 - x

[OH⁻] = 0,04515 - x

Replacing in (1) you will obtain:

x² - 6,7907x + 0,3025 = 0

Solving for x:

x = 6,74586 No physical sense

x = 0,04484 Real answer.

Thus, [OH⁻] = 0,04515 - 0,044842 = 3,08x10⁻⁴M

pOH = 3,51.

<em>pH = 10,49</em>

Thus ΔpH is 12,65 - 10,49 = <em>2,16 ≈ 2,17</em>

I hope it helps!

4 0
4 years ago
what is the purpose of the condenser? question 3 options: a) to de-superheat the entering vapor, condense the vapor to a liquid,
Alona [7]

Option (a) is correct,

the purpose of the condenser is to de-superheat, the entering vapor, condense the vapor to a liquid, and subcool the liquid.

<h3>What is a condenser's purpose?</h3>

A condenser uses a cooling fluid to attempt to sufficiently cool down a vapor, changing its state from a vapor to a liquid. Condensers come in a variety of designs, including direct condensing, which involves coming into direct touch with the cooling fluid and the vapor.

<h3>What kind of vapor is condensed?</h3>

The vapour that needs to condense might be highly different and can even include non-condensable vapour, such as air, which greatly affects how well the condenser works.

Learn more about condenser here:-

brainly.com/question/12138870

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7 0
2 years ago
What are the major specials presents in a solution of a strong acid like HCl
lubasha [3.4K]

Answer:

hydrogen ions (H⁺) and chloride ions (Cl⁻)

Explanation:

Hydrochloric acid (HCl) is a strong acid. That means that the compound dissociates completely into ions when is dissolved in water, as follows:

HCl → H⁺ + Cl⁻

The equilibrium is completely shifted to the right side (products). Thus, it is considered that the concentration of the non-dissociated compound (HCl) is negligible, and the major specials present in the solution are the hydrogen ions (H⁺) and chloride ions (Cl⁻).

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3 years ago
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tekilochka [14]

Answer:

4

Explanation:

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