Answer: The volume for 0.850 mol of
from a
solution is 1700 mL.
The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
Explanation:
Molarity is the number of moles of solute present in a liter of solution.
- As given moles of
are 0.850 mol and molarity of
solution is 0.5 M. Hence, its volume is calculated as follows.

Therefore, the volume for 0.850 mol of
from a
solution is 1700 mL.
- As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

So, volume for LiOH solution is calculated as follows.

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
Answer:
0.0064 qt
Explanation:
Given data:
Density of mercury = 13.6 g/cm³
Mass of mercury = 83.0 g
How many quarts mercury have = ?
Solution:
First of all we will calculate the volume in cm³.
d = m/v
13.6 g/cm³ = 83.0 g / volume
Volume = 83.0 g / 13.6 g/cm³
Volume = 6.1 cm³
cm³ to L:
6.1 cm³ × 1 L / 1000 cm³
0.0061 L
In quarts:
1 L = 1.06 qt
0.0061 L × 1.06 qt / 1 L
0.0064 qt
Answer:
Explanation:
2. The lone pairs on the nitrogen atoms do contribute to aromaticity.
3. The lone pairs on the nitrogen atoms occupy sp2 hybridized orbitals.
5. One of the two lone pairs on the oxygen atom (inside the ring) occupies a p orbital, giving a continuous system of overlapping p orbitals containing six electrons.
First i wanted to say you look preety LOL
1) Determine the rate constant for the reaction:
<span>k = (ln 2) / t_1/2 <--- I'll leave you to figure out how that came to be. Hint: use the integrate form of the first-order rate law </span>
<span>k = (ln 2) / 23.6 min </span>
<span>k = 0.02937 min^-1 <--- keep a few extra digits </span>
<span>1) use the integrated form of the first-order rate law: </span>
<span>ln A = -kt + ln A_o </span>
<span>ln A = - (0.02937 min^-1) (120 min) + ln 2.50 </span>
<span>ln A = -3.5244 + 0.91629 </span>
<span>ln A = -2.60811 </span>
<span>A = 0.07367 M <--- round off more as you see fit </span>
<span>Here's another way: </span>
<span>120 min / 23.6 min = 5.106383 half-lives </span>
<span>(0.5)^5.106383 = 0.02902856 <--- the decimal amount remaining after 5.106383 half-lives </span>
<span>0.02902856 x 2.50 M = the answer</span>