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Natali [406]
1 year ago
11

Dentify the reagents used to carry out the chlorination of benzene. a. cl2/ccl4 b. cl2/fecl3 c. cl2/nacl d. both b and c e. a, b

and c
Chemistry
1 answer:
algol131 year ago
8 0

The reagents which are used to carry out the chlorination of benzene are   cl2/fecl3 and cl2/nacl

Chlorination is the process of disinfecting drinking water by introducing chlorine to eradicate viruses, germs, and parasites. To get drinking water with safe levels of chlorine, various techniques can be utilized. Chlorination is the technique of disinfecting and eradicating bacteria from drinking water by adding chlorine to it.

To get drinking water with safe levels of chlorine, various techniques can be utilized. Chlorine can be found as solid calcium hypochlorite (Ca(OCl)2), sodium hypochlorite solution (NaOCl), or compressed elemental gas. Chlorine is added to water as part of the chlorination process, however the chlorinating substance need not be pure chlorine.

To learn more about chlorination please visit -
brainly.com/question/14962130
#SPJ4

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Calculate the volume, in milliliters, for the following:
fredd [130]

Answer: The volume for 0.850 mol of NaNO_{3} from a NaNO_{3} solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

  • As given moles of NaNO_{3} are 0.850 mol and molarity of NaNO_{3} solution is 0.5 M. Hence, its volume is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL

Therefore, the volume for 0.850 mol of NaNO_{3} from a NaNO_{3} solution is 1700 mL.

  • As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol

So, volume for LiOH solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

6 0
3 years ago
The density of mercury is 13.6 g/cm'. How many quarts does 83.0 g of Hg occupy? (1 L=1.06 qt)​
forsale [732]

Answer:

0.0064 qt

Explanation:

Given data:

Density of mercury = 13.6 g/cm³

Mass of mercury = 83.0 g

How many quarts mercury have = ?

Solution:

First of all we will calculate the volume in cm³.

d = m/v

13.6 g/cm³ = 83.0 g / volume

Volume = 83.0 g /  13.6 g/cm³

Volume = 6.1 cm³

cm³ to L:

6.1 cm³ × 1 L / 1000  cm³

0.0061 L

In quarts:

1 L = 1.06 qt

0.0061 L × 1.06 qt / 1 L

0.0064 qt

4 0
3 years ago
Why do you think Scientists around the world prefers to use SI units instead of other kinds of units??
STatiana [176]

Answer: LOL

Explanation:

7 0
2 years ago
Choose the correct explanations for the aromaticity of the compound.
Vlad1618 [11]

Answer:

Explanation:

2. The lone pairs on the nitrogen atoms do contribute to aromaticity.

3. The lone pairs on the nitrogen atoms occupy sp2 hybridized orbitals.

5. One of the two  lone pairs on the oxygen atom (inside the ring) occupies a p orbital, giving a continuous system of overlapping p orbitals containing six electrons.

5 0
3 years ago
A reaction known to be first-order has a half-life of 23.6 min. If the initial concentration of the reactant is 2.50 M, what wil
Scrat [10]
First i wanted to say you look preety LOL

1) Determine the rate constant for the reaction: 

<span>k = (ln 2) / t_1/2 <--- I'll leave you to figure out how that came to be. Hint: use the integrate form of the first-order rate law </span>

<span>k = (ln 2) / 23.6 min </span>

<span>k = 0.02937 min^-1 <--- keep a few extra digits </span>

<span>1) use the integrated form of the first-order rate law: </span>

<span>ln A = -kt + ln A_o </span>

<span>ln A = - (0.02937 min^-1) (120 min) + ln 2.50 </span>

<span>ln A = -3.5244 + 0.91629 </span>

<span>ln A = -2.60811 </span>

<span>A = 0.07367 M <--- round off more as you see fit </span>

<span>Here's another way: </span>

<span>120 min / 23.6 min = 5.106383 half-lives </span>

<span>(0.5)^5.106383 = 0.02902856 <--- the decimal amount remaining after 5.106383 half-lives </span>

<span>0.02902856 x 2.50 M = the answer</span>

8 0
3 years ago
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