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zvonat [6]
2 years ago
15

I need this tonight. I will give brainliest

Chemistry
1 answer:
yuradex [85]2 years ago
4 0

Answer:

sorry but it's so hard to do this

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How to calculate the sum of the ratio of the ions
ANEK [815]
If it is just ratio you must just put the mass number on the either side of the symbol ‘:’ and cancel but the same process is not used to find simplest ratio
6 0
3 years ago
Three separate 3.5g blocks of al, cu, and fe at 25°c each absorb 0.505 kj of heat. which block reaches the highest temperature?
77julia77 [94]

The energy can be shown as:

Q = ms dT

Whereas, m is the mass of block

s is specific heat

dT is change in temperature.

Copper block having the lowest specific heat and thus having the higher change in temperature and therefore having the higher final temperature.

8 0
3 years ago
If a solution has a pOH of 8.71, what is the [H+]?
TEA [102]

Answer: 5.1\times 10^{-6}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH+pOH=14

Putting in the values:

pH=14-8.71=5.29

5.29=-log[H^+]

[H^+]=5.1\times 10^{-6}

Thus [H^+] is 5.1\times 10^{-6}M

6 0
4 years ago
Calculate the mass percent (m/m) of a solution prepared by dissolving 51.56 g of NaCl in 164.2 g of H2O. Express your answer to
denis-greek [22]

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = Mass \ of \ (NaCl+H_2O)

                                 = 51.56+164.2

                                 = 215.76 \ g

hence,

⇒ Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100

                           =\frac{51.56}{215.76}\times 100

                           =23.896 \ percent

4 0
3 years ago
There are three isotopes of X element (X):
Nutka1998 [239]

Answer:

Average atomic mass = 17.5 amu.

Explanation:

Given data:

X-17 isotope = atomic mass17.2 amu, abundance:78.99%

X-18isotope =  atomic mass 18.1 amu, abundance 10.00%

X-19isotope = atomic mass:19.1 amu, abundance: 11.01%

Average atomic mass of X = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (78.99×17.2)+(10.00×18.1) +(11.01+ 19.1) /100

Average atomic mass =  1358.628 + 181 +210.291 / 100

Average atomic mass  = 1749.919 / 100

Average atomic mass = 17.5 amu.

8 0
3 years ago
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