How many equivalent resonance forms can be drawn for so2 without expanding octet on the sulfur atom? (sulfur is the central atom
.)how many equivalent resonance forms can be drawn for so2 without expanding octet on the sulfur atom? (sulfur is the central atom.)?
2 answers:
Answer:
Two equivalent resonance forms can be drawn
Explanation:
In Lewis structure, total valence electrons of constituting atoms are used to draw structure by obeying octet of all atoms and duet of hydrogen atoms.
Least electronegative atom (except hydrogen atom) are considered as central atom.
In , S is the least electronegative atom. Hence it is the central atom.
Number of valence electron of S is 6 and valence electron of O is 6.
So, total number of valence electrons in is 18.
By using this 18 electrons and obeying octet for S and O, two equivalent resonance forms can be drawn.
Structure of resonance forms has been given below.
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Answer: Rate law=, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is
Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
k= rate constant
x = order with respect to A
y = order with respect to A
n = x+y = Total order
a) From trial 1: (1)
From trial 2: (2)
Dividing 2 by 1 :
therefore y=2.
b) From trial 2: (3)
From trial 3: (4)
Dividing 4 by 3:
, x=1
Thus rate law is
Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.
c) For calculating k:
Using trial 1:
.