Hey there!:
HA <=> H⁺ + A⁻
pH = -log[H+] = 6
[ H⁺ ] = 10^-pH
[ H⁺] = 10 ^ -6
[ H⁺ ] = 0.000001 M
Percent dissociation:
[ H⁺ ] / [ HA]o * 100
[ 0.000001 / 0.10 ] * 100
0.00001 * 100 => 0.0010%
Answer D
Hope that helps!
Answer: 195.3 K
Explanation: Use Charles Law to get T2
Charles Law V1 / T1 = V2 / T2
Derive the equation to find T2
T2 = V2T1 / V1
Convert temperature into K
T1 = 20.0 °C + 273 = 293 K
Substitute the values:
4.00 L x 293 K / 6.00 L = 195. 3 K
Answer:
Follows are the solution to this question:
Explanation:
Please find the complete solution in the attached file.