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3 years ago

8

Jane bought some raisins to keep in her purse as a snack what is one reason raisins dont need refrigeration

2 answers:

iragen [17]3 years ago

6 0

Answer: The drying process worked to preserve them

Explanation: apex

adell [148]3 years ago

4 0

Raisins are dried up grapes. The drying process worked on preserving raisins. Most of the water contained in them was removed during the drying process. This dry environment is not suitable for bacteria to breed in and, thus, raisins won't go rancid.

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Please help me with these I'll give 15 points

VLD [36.1K]

1.d
2.g
3.j
4.i
5.c
6.h
7.e
8.b
9.a
10.f

5 0

3 years ago

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What are the two processes underlying this image that turn peat into coal

Travka [436]

Answer:

Peatification and coalification

Explanation:

https://energyeducation.ca/encyclopedia/Coal_formation

8 0

3 years ago

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Controls are defined as ____

wariber [46]

Answer:

The second one is the answer

4 0

3 years ago

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Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is

Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal = $C_{134}H_{96}O_{9}NS$

Molecular mass of coal = $(134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm$

Let’s calculate the mass of nitrogen in coal

$Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}$

$Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%$

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = $4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons$

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0

3 years ago

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Electrochemical cells can be used to measure ionic concentrations. A cell is set up with a pair of Zn electrodes, each immersed

Phantasy [73]

Answer:

the concentration of the solution is 0.00906 M

Explanation:

Given the data in the question;

we know that from Nernst Equation;

E = E⁰ - ((0.0592/n) logQ)

now, E₀ for concentration cell is 0

n for this redox is 2

concentration of the unknown solution is x

so we substitute

0.045 = 0 - ( 0.0592 / 2)log( x/0.300 ))

0.045 = -0.0296log( x/0.300 )

divide both side by 0.0296

1.52 = -log( x/0.300 )

x/0.300 = $10^{-1.52$

x/0.300 = 0.0301995

we cross multiply

x = 0.300 × 0.0301995

x = 0.00906 M

Therefore, the concentration of the solution is 0.00906 M

6 0

3 years ago