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elena-14-01-66 [18.8K]
2 years ago
14

Infer What happens to a liquid that is not in a container ?

Chemistry
2 answers:
LenKa [72]2 years ago
7 0

Answer:

it will evaoprate over time

Explanation:

Sergeeva-Olga [200]2 years ago
5 0

Answer:

wdym ur confusing me

Explanation:

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Please help me.<br><br>balance this equation <br><br>Al + 0(2) = Al0(3)
Gala2k [10]
What helps me to balance equations is to list the elements i have on each side of the equation, and use tally marks to see what I have and don't have. Then when I'm done balancing, I tally again to make sure everything matches up.
On the left side, you have 1 Al, and 2 O. On the right side, 1 Al and 3 O.
In order for the equation to balance, you need to place a 2 in front of the AlO on the right side. This would make the Al have 2 atoms and the O have six. On the left side, you need to place a 2 in front of the Al and a 3 in front of the O, making it six. Left side: 2 Al's 6 O's. Right side: 2 Al's and 6 O's. Matches!
4 0
3 years ago
150 mL of 0.25 mol/L magnesium chloride solution and 150 mL of 0.35 mol/L silver nitrate solution are mixed together. After reac
Murljashka [212]

Answer:

0.175\; \rm mol \cdot L^{-1}.

Explanation:

Magnesium chloride and silver nitrate reacts at a 2:1 ratio:

\rm MgCl_2\, (aq) + 2\, AgNO_3\, (aq) \to Mg(NO_3)_2 \, (aq) + 2\, AgCl\, (s).

In reality, the nitrate ion from silver nitrate did not take part in this reaction at all. Consider the ionic equation for this very reaction:

\begin{aligned}& \rm Mg^{2+} + 2\, Cl^{-} + 2\, Ag^{+} + 2\, {NO_3}^{-} \\&\to  \rm Mg^{2+} + 2\, {NO_3}^{-} + 2\, AgCl\, (s)\end{aligned}.

The precipitate silver chloride \rm AgCl is insoluble in water and barely ionizes. Hence, \rm AgCl\! isn't rewritten as ions.

Net ionic equation:

\begin{aligned}& \rm Ag^{+} + Cl^{-} \to AgCl\, (s)\end{aligned}.

Calculate the initial quantity of nitrate ions in the mixture.

\begin{aligned}n(\text{initial}) &= c(\text{initial}) \cdot V(\text{initial}) \\ &= 0.25\; \rm mol \cdot L^{-1} \times 0.150\; \rm L \\ &= 0.0375\; \rm mol \end{aligned}.

Since nitrate ions \rm {NO_3}^{-} do not take part in any reaction in this mixture, the quantity of this ion would stay the same.

n(\text{final}) = n(\text{initial}) = 0.0375\; \rm mol.

However, the volume of the new solution is twice that of the original nitrate solution. Hence, the concentration of nitrate ions in the new solution would be (1/2) of the concentration in the original solution.

\begin{aligned} c(\text{final}) &= \frac{n(\text{final})}{V(\text{final})} \\ &= \frac{0.0375\; \rm mol}{0.300\; \rm L} = 0.175\; \rm mol \cdot L^{-1}\end{aligned}.

6 0
3 years ago
Bromophenol blue is the indicator used in detecting the endpoint for the antacid analysis in this experiment. what is the expect
Paul [167]
Hello!

For the antacid analysis, the chemical reactions that occur in the titration are the following ones:

First, the antacid (composed of weak bases and carbonates) is completely neutralized by the H⁺ ions in the HCl

2HCl + CaCO₃ → CO₂ + H₂O + 2CaCl₂

HCl + OH⁻ → H₂O + Cl⁻

The titration reaction consists in titrating the excess H⁺ ions that are left in the solution, by the following reaction:

H⁺ + NaOH → H₂O + Na⁺

So, when the equivalence point is reached, the solution will go from acid to basic. As bromophenol blue is yellow in acidic solution and blue in basic solution, you'll expect the indicator to change from yellow to blue.

Have a nice day!
7 0
2 years ago
Which best describes how isotopes of the same element differ?
Tasya [4]
It would be C!!!!!!!!!!!!!
8 0
3 years ago
Maria wants to determine which type of disinfectant kills the most bacteria.
murzikaleks [220]

Answer:

well she can test both of the soap by putting one on and plate and another on the other plate and which ever is cleaner is your answer

6 0
3 years ago
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