Answer:
On google it says this: HF will be the most soluble in water. Substances which form hydrogen bonding with polar water molecules are soluble in water. F has the highest electronegativity amongst other halogens.
Idk maybe A?
Explanation:
The water molecule<span> has two </span>hydrogen<span> atoms joined to one </span>oxygen<span> atom by single covalent bonds. </span>Because oxygen is more electronegative than hydrogen<span>, the electrons of the covalent bond spend </span>more <span>time closer to the </span>oxygen<span> then </span>hydrogen<span> which creates a polar covalent bond. Hope this answers your question. Have a great day!</span>
Answer:
8 to 1.
Explanation:
- Oxygen combines with hydrogen atoms to form water according to the balanced equation:
<em>O₂ + 2H₂ → 2H₂O.</em>
It is clear that one mole of oxygen combines with two moles of hydrogen atoms to form 2 moles of water.
So, the molar ratio of oxygen to hydrogen is (1 to 2).
- The mass of 1 mole of oxygen = (no. of moles)(molar mass) = (1 mol)(32.0 g/mol) = 32.0 g.
- The mass of 2 moles of hydrogen = (no. of moles)(molar mass) = (2 mol)(2.0 g/mol) = 4.0 g.
<em>So, the mass ratio of oxygen to hydrogen (32.0 g/4.0 g) = (8: 1).</em>
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Answer:
The equilibrium pressure of NO2 is 0.084 atm
Explanation:
Step 1: Data given
A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO3.
Kp = 0.0118
Step 2: The balanced equation
NO( g) + SO3( g) ⇌ NO2( g) + SO2( g)
Step 3: The initial pressures
p(NO) = 0.86 atm
p(SO3) = 0.86 atm
p(NO2) = 0 atm
p(SO2) = 0 atm
Step 4: The pressure at the equilibrium
For 1 mol NO we need 1 mol SO3 to produce 1 mol NO2 and 1 mol SO2
p(NO) = 0.86 -x atm
p(SO3) = 0.86 -xatm
p(NO2) = x atm
p(SO2) = x atm
Step 5: Define Kp
Kp = ((pNO2)*(pSO2)) / ((pNO)*(pSO3))
Kp = 0.0118 = x²/(0.86 - x)²
X = 0.08427
p(NO) = 0.86 -0.08427 = 0.77573 atm
p(SO3) = 0.86 -0.08427 = 0.77573 atm
p(NO2) = 0.08427 atm
p(SO2) = 0.08427 atm
The equilibrium pressure of NO2 is 0.08427 atm ≈ 0.084 atm
