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oksian1 [2.3K]
3 years ago
15

How are the boiling point and freezing point of a solvent affected when a solute is added?

Chemistry
2 answers:
____ [38]3 years ago
7 0
<span>When a solute is added to a solvent, some properties are affected and these set of properties are called colligative properties. The properties depend on the amount of solute dissolved in a solvent. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering.<span> </span></span>
aliya0001 [1]3 years ago
4 0

Answer:

The boiling point increases and freezing point decreases on addition of non volatile solute in a solvent.

Explanation:

When we add a non volatile solute in a volatile solvent, the vapor pressure of the resulting solution is lower than the vapor pressure of pure solvent. Due to decrease in vapor pressure:

a) The temperature required to boil the solution increases (boiling point is the temperature at which the vapor pressure of a liquids is equal to atmospheric pressure). This is known as elevation in boiling point. It is a colligative property which depends upon number of solute particles.

b) The temperature required to freeze a liquid decreases and this is known as depression in freezing point, which is also a colligative property which depends upon number of solute particles.

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Ede4ka [16]
Atomic mass of Br = 79.904 
<span>Now  lets say  y%  is abundance of 79Br. </span>
<span>Then abundance of 81Br = (100 - y) </span>
<span>mass due to 79Br = 78.9183 * y/100 = 0.789183y
</span><span>mass due to 81Br = 80.9163 x (100 - y)/100 = 0.809163(100 - y) </span>
<span>Therfore</span>
<span>0.789183y+ 0.809163(100 - y) = 79.904 </span>
<span>0.789183y + 80.9163 - 0.809163y = 79.904 </span>
<span> - 0.01998y= 79.904 - 80.9163
 = - 1.0123 </span>
<span>y = 1.0123/0.01998 = 50.67% </span>
<span> 79Br = 50.67% </span>
<span>now
 81Br = 100 - 50.67 = 49.33%
hope this helps</span>
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