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oksian1 [2.3K]
3 years ago
15

How are the boiling point and freezing point of a solvent affected when a solute is added?

Chemistry
2 answers:
____ [38]3 years ago
7 0
<span>When a solute is added to a solvent, some properties are affected and these set of properties are called colligative properties. The properties depend on the amount of solute dissolved in a solvent. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering.<span> </span></span>
aliya0001 [1]3 years ago
4 0

Answer:

The boiling point increases and freezing point decreases on addition of non volatile solute in a solvent.

Explanation:

When we add a non volatile solute in a volatile solvent, the vapor pressure of the resulting solution is lower than the vapor pressure of pure solvent. Due to decrease in vapor pressure:

a) The temperature required to boil the solution increases (boiling point is the temperature at which the vapor pressure of a liquids is equal to atmospheric pressure). This is known as elevation in boiling point. It is a colligative property which depends upon number of solute particles.

b) The temperature required to freeze a liquid decreases and this is known as depression in freezing point, which is also a colligative property which depends upon number of solute particles.

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How many chlorine atoms are in each set?<br> six calcium chloride formula units.
Aleonysh [2.5K]

Answer:

tae ko malutong

Explanation:

dahil utong ko maitim

3 0
3 years ago
Un ácido nítrico tiene una densidad de 10% ,calcular el peso de 1000 centímetros cúbicos
devlian [24]
D = M/V
D = 0.10
V = 1000 cm^3

0.10 = M / 1000
M = 100

Porque la densidad es 10%, se puede usar 0.10 en este formulario para calcular el peso. No sé lo que es la unidad para el peso pero es 100.
4 0
3 years ago
Can you give me more explanation in the picture?
PolarNik [594]
Read the paper more carefully if you don't understand it
5 0
3 years ago
How many molecules are in 41.8 g of sulfuric acid
Anton [14]

Answer

× 10²³ molecules are in 41.8 g of sulfuric acid

Explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol

Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

Therefore, 0.426187053 moles of sulfuric acid is equal

\frac{0.426187053\text{ }mol}{1\text{ }mol}\times6.022×10²³\text{ }molecules=2.57\times10^{23}\text{ }molecules

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.

3 0
1 year ago
What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 mole of c
yuradex [85]

Answer:

Theoretical moles of V are 1.6 moles

Explanation:

The theoretical yield of a reaction is defined as the amount of product you would make if all of the limiting reactant was converted into product.

In the reaction:

V2O5(s) + 5Ca(i) → 2V(i) + 5CaO(s)

Based on the reaction, 1 mol of V2O5 needs 5 moles of Ca for a complete reaction. As there are just 4 moles, <em>limiting reactant is Ca.</em> As there are produced 2 moles of V per 5mol of Ca, Theoretical moles of V are:

4 moles of Ca × (2mol V / 5Ca) = <em>1.6 moles of V</em>

<em></em>

I hope it helps!

5 0
3 years ago
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