Answer:
The initial volume of Ne gas is 261mL
Explanation:
This question can be answered using Ideal Gas Equation;
However, the following are the given parameters
Initial Pressure = 654mmHg
Finial Pressure = 345mmHg
Final Volume = 495mL
Required
Initial Volume?
The question says that Temperature is constant;
This implies that, we'll make use of Boyle's law ideal gas equation which states;
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
Where
represent the initial pressure
represent the final pressure
represent the initial temperature
represent the final temperature
![P_1 = 654mmHg\\P_2 = 345mmHg\\V_2 = 495mL](https://tex.z-dn.net/?f=P_1%20%3D%20654mmHg%5C%5CP_2%20%3D%20345mmHg%5C%5CV_2%20%3D%20495mL)
Substitute these values in the formula above;
![654 * V_1 = 345 * 495](https://tex.z-dn.net/?f=654%20%2A%20V_1%20%3D%20345%20%2A%20495)
![654V_1 = 170775](https://tex.z-dn.net/?f=654V_1%20%3D%20170775)
Divide both sides by 654
![\frac{654V_1}{654} = \frac{170775}{654}](https://tex.z-dn.net/?f=%5Cfrac%7B654V_1%7D%7B654%7D%20%3D%20%5Cfrac%7B170775%7D%7B654%7D)
![V_1 = \frac{170775}{654}](https://tex.z-dn.net/?f=V_1%20%3D%20%5Cfrac%7B170775%7D%7B654%7D)
![V_1 = 261.123853211](https://tex.z-dn.net/?f=V_1%20%3D%20261.123853211)
(Approximated)
<em>The initial volume of Ne gas is 261mL</em>
Density= mass/volume
= 100/25
density = 4g/ml
<u>Answer:</u> Increasing temperature
<u>Explanation:</u>
The Principle of Le Chatelier states that <u>if a system in equilibrium is subjected to a change of conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.
</u>
The variation of one or several of the following factors can alter the equilibrium condition in a chemical reaction:
- Temperature
- The pressure
- The volume
- The concentration of reactants or products
In the case of the reaction in the question, <u>the change that moves the balance to the left will be the one that moves it towards the reagents</u>, that is, that favors the production of reagents instead of products.
-
Decreasing the concentration of SO3 and increasing the concentration of SO2 <u>will favor the production of SO3</u>, which is the product of the reaction.
- Decreasing the volume increases the pressure of the system and the balance will move to where there is less number of moles. In the case of the reaction in question, we have 3 moles of molecules in the reactants (1 mole of O2 + 2 moles of SO2) while in the products there are 2 moles of SO3 only, therefore, <u>decreasing the volume will displace the balance to the right</u>, which corresponds to the sense in which there is less number of moles.
The reaction of the question is an exothermic since ΔH <0, therefore in the reaction heat is produced and it can be written in the following way,
2SO2(g) + O2(g) ⇌ 2SO3(g) + heat
- So, if we increase the temperature we will be adding heat to the system, so the balance would move to the left to compensate for the excess heat in the system.
Answer:
The molarity of the solution is 7.4 mol/L
Explanation:
From the question above
0.400 ml of water contains 1.00 g of hydrochloride form of cocaine
Therefore 1000 ml of water will contain x g of hydrochloride form of cocaine
x = 1000 / 0.400
x = 2500 g
2500g of hydrochloride form of cocaine is present in 1000 ml of water.
Mole of hydrochloride form of cocaine = mass /molar mass of hydrochloride
Mole of hydrochloride form of cocaine = 2500/339.8
= 7.4 mol
Molarity = mol/ volume in liter (L)
molarity = 7.4 /1
Molarity = 7.4 mol/L