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zloy xaker [14]
3 years ago
10

2(4x – 3) ≥ –3(3x) + 5x?Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8?

Mathematics
1 answer:
nika2105 [10]3 years ago
5 0

Answer:

x<=-1/2

Step-by-step explanation:

An inequality is a mathematical relationship that compares two unequal numbers using the number line

To solve the inequality 2x – 6 ≥ 6(x – 2) + 8

We first simplify both sides of the inequality

2x-6≥6x-12+8

2x-6≥6x-4

Add 6 to both sides

2x≥6x+2

-4x≥2

x≥2/-4

Sign changes when we divide both sides of equation by a negative sign

x<=-1/2

Therefore x is less than or equal to -1/2 on the number line

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Here is a triangular pyramid and its net.
bazaltina [42]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

3 0
3 years ago
Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11
Alexus [3.1K]

Answer:\frac{-7\sqrt{2} }{4}

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get \sqrt{16}-x\sqrt{8} =11. We know that the square root of 16 is ±4, so now our equation is ±4 - x\sqrt{8}=11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - x\sqrt{8}=11. We can use inverse operations to make the a little easier to solve: -7= x\sqrt{8}. We divide both sides by \sqrt{8} to get \frac{-7}{\sqrt{8} } =x, which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by \frac{\sqrt{8} }{\sqrt{8} } (which is equal to one so we can use it) which is equal to \frac{-7\sqrt{8} }{8}. Let's finish this by simplifying it. \sqrt{8} =2\sqrt{2} (2x2^{2}). We can simplify it further by simplifying the 2, making it \frac{-7\sqrt{2} }{4}.

Hope this wasn't too confusing! I'll answer any questions.

8 0
3 years ago
Read 2 more answers
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
2 years ago
What are the coordinates of the point LaTeX: \frac{3}{4}\:3 4of the way from A to B? coordinate plane with line segment AB. Poin
egoroff_w [7]

Answer: \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

We need to find the coordinates of the point which is 3/4 of the way from A to B.

Let the required point be P.

AP:AB=3:4

AP:PB=AP:(AB-AP)=3:(4-1)=3:1

It means, point P divides segment AB in 3:1.

Section formula:  If a point divides a line segment in m:n, then

\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Using section formula, we get

P=\left(\dfrac{3(-3)+1(-5)}{3+1},\dfrac{3(3)+1(-4)}{3+1}\right)

P=\left(\dfrac{-9-5}{4},\dfrac{9-4}{4}\right)

P=\left(\dfrac{-14}{4},\dfrac{5}{4}\right)

P=\left(\dfrac{-7}{2},\dfrac{5}{4}\right)

Therefore, the required point is \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

6 0
3 years ago
Qasim and Alejandra both earn $15 an hour at their job. This week Alejandra worked three hours more than Qasim. If h represents
joja [24]

Answer:

Alejandra worked 8 hours and Qasim worked 5

Step-by-step explanation:

195/15 is 13. They worked 13 hours in total. 8 is 3 more than 5 and together they equal 13.

8 0
3 years ago
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