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vivado [14]
3 years ago
14

An object has a mass of 6.8 g and volume of 34 mL. What is the density of the object?​

Chemistry
1 answer:
jenyasd209 [6]3 years ago
7 0

Answer:

<h2>Density = 0.2 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

From the question the points are

mass = 6.8 g

volume = 34 mL

Substitute the values into the above formula and solve

That's

<h3>Density =  \frac{6.8}{34}</h3>

We have the final answer as

<h3>Density = 0.2 g/mL</h3>

Hope this helps you

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A student analyzed an unknown sample that contained a single anion. The sample gave a yellow precipitated upon addition of a sol
kenny6666 [7]
<h3>Answer:</h3>

Anion present- Iodide ion (I⁻)

Net ionic equation- Ag⁺(aq) + I⁻(aq) → AgI(s)

<h3>Explanation:</h3>

In order to answer the question, we need to have an understanding of insoluble salts or precipitates formed by silver metal.

Additionally we need to know the color of the precipitates.

Some of insoluble salts of silver and their color include;

  • Silver chloride (AgCl) - white color
  • Silver bromide (AgBr)- Pale cream color
  • Silver Iodide (AgI) - Yellow color
  • Silver hydroxide (Ag(OH)- Brown color

With that information we can identify the precipitate of silver formed and identify the anion present in the sample.

  • The color of the precipitate formed upon addition of AgNO₃ is yellow, this means the precipitate formed was AgI.
  • Therefore, the anion that was present in the sample was iodide ion (I⁻).
  • Thus, the corresponding net ionic equation will be;

Ag⁺(aq) + I⁻(aq) → AgI(s)

4 0
3 years ago
How many calories are absorbed in a process that absorbs 0.128 joules?
earnstyle [38]

Answer:

There are 0.0305 calories in 0.128 joules

Explanation:

Given that,

Heat absorbed, Q = 0.128 J

We need to find the heat energy absorbed in calories.

We know that the relation between joules and calories is as follows :

1 calorie = 4.184 J

1 J = (1/4.184) J

So,

0.128\ J=\dfrac{0.128 }{4.184}\\\\=0.0305\ cal

So, there are 0.0305 calories in 0.128 joules

7 0
3 years ago
What volume of 12M HCI is needed to prepare 250<br> of 0.20M HCI?
Alchen [17]

Answer: 4.2

Explanation:

M_{A}V_{A}=M_{B}V_{B}\\(12)V_{A}=(250)(0.20)\\V_{A}=\frac{(250)(0.20)}{12}=\boxed{4.2}

6 0
2 years ago
Consider a closed containing a solid in equilibrium with its vapor. The volume of the solid is much less than that of the contai
Furkat [3]

Answer:

Explanation:

check the attachment below

5 0
3 years ago
Write the balanced NET IONIC equation for the reaction that occurs when ammonium nitrate and potassium hydroxide are combined. N
vova2212 [387]

Answer:

Net Ionic equation

NH₄⁺ + OH⁻ → NH₃ + H₂O

Option B is correct.

Weak Acid Strong Base

Check Explanation for the extent of the reaction.

Explanation:

Ammonium nitrate = NH₄NO₃

Potassium Hydroxide = KOH

Ammonium salts combine with alkalis to liberate NH₃ and form water.

The two reactants combine to give

NH₄NO₃ + KOH → KNO₃ + NH₃ + H₂O

In ionic form,

- NH₄NO₃ exists as NH₄⁺ and NO₃⁻

- KOH exists as K⁺ and OH⁻

- KNO₃ as K⁺ and NO₃⁻

And NH₃ and H₂O stay as they are, as per covalent compounds.

So, we have

NH₄⁺ + NO₃⁻ + K⁺ + OH⁻ → K⁺ + NO₃⁻ + NH₃ + H₂O

Eliminating the ions that exist on both sides, we have the net ionic equation to be

NH₄⁺ + OH⁻ → NH₃ + H₂O

which shows that this reaction is essentially a neutralization reaction in which the Bronsted Lowry acid, NH₄⁺, loses its proton to the base, OH⁻ and gives conjugate base, NH₃ and conjugate acid, H₂O.

This reaction is classified as a Weak acid versus Strong Base reaction as NH₄⁺ is from a Weak acid and OH⁻ is from a strong base.

Since this reaction is between a Weak base and a strong acid, the ionization isn't expected to be 100%, Hence, the extent of this reaction will be any option that is not 100%, a couple pieces of information might be required for the correct estimate, but above 50% seems correct.

Hope this Helps!!!

8 0
3 years ago
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