Answer:
c. carbon monoxide
Explanation:
no one bothers to read why anyways so look at the picture
Answer : The final temperature of the metal block is, ![25^oC](https://tex.z-dn.net/?f=25%5EoC)
Explanation :
![heat_{absorbed}=heat_{released}](https://tex.z-dn.net/?f=heat_%7Babsorbed%7D%3Dheat_%7Breleased%7D)
As we know that,
![Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})](https://tex.z-dn.net/?f=Q%3Dm%5Ctimes%20c%5Ctimes%20%5CDelta%20T%3Dm%5Ctimes%20c%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29)
.................(1)
where,
q = heat absorbed or released
= mass of aluminum = 55 g
= mass of water = 0.48 g
= final temperature = ?
= temperature of aluminum = ![25^oC](https://tex.z-dn.net/?f=25%5EoC)
= temperature of water = ![25^oC](https://tex.z-dn.net/?f=25%5EoC)
= specific heat of aluminum = ![0.900J/g^oC](https://tex.z-dn.net/?f=0.900J%2Fg%5EoC)
= specific heat of water= ![4.184J/g^oC](https://tex.z-dn.net/?f=4.184J%2Fg%5EoC)
Now put all the given values in equation (1), we get
![55g\times 0.900J/g^oC\times (T_{final}-25)^oC=-[0.48g\times 4.184J/g^oC\times (T_{final}-25)^oC]](https://tex.z-dn.net/?f=55g%5Ctimes%200.900J%2Fg%5EoC%5Ctimes%20%28T_%7Bfinal%7D-25%29%5EoC%3D-%5B0.48g%5Ctimes%204.184J%2Fg%5EoC%5Ctimes%20%28T_%7Bfinal%7D-25%29%5EoC%5D)
![T_{final}=25^oC](https://tex.z-dn.net/?f=T_%7Bfinal%7D%3D25%5EoC)
Thus, the final temperature of the metal block is, ![25^oC](https://tex.z-dn.net/?f=25%5EoC)
You have to take the 476 L and divide it by 22.4 because with Molar Volume 1 mol = 22.4L. After you divide it your answer is 21.25.
Volume of the gas is 525 L.
<u>Explanation:</u>
It is given that the volume of the gas divided by the temperature is 1.75.
V/T = 1.75
As per the Charles law, volume is proportional to the temperature.
V ∝ T
V/T = constant
Now we have to find V, and T is given as 300 K.
So plugin the values as,
V/300 = 1.75
Rearranging the equation to get V as,
V = 1.75×300
= 525 L
Answer:
K I will attempt
Explanation:
a)
![O_2_{(g)}+ 2H_2_{(g)} => 2H_2O_{(l)}\\](https://tex.z-dn.net/?f=O_2_%7B%28g%29%7D%2B%202H_2_%7B%28g%29%7D%20%3D%3E%202H_2O_%7B%28l%29%7D%5C%5C)
b)
1 : 2 : 2 (I don't know if this is what the question wants but it is what I would answer)
c)
Hydrogen because it requires 2 moles of H2 to react with 1 mole of O2
d)
24 moles of water. Look at stoichiometric coefficient. 2:2 means 24 moles you get 24 moles
e)
Oxygen. 2 < 5/2. Remember, 1 mole of O2 requires 2 moles of H2. But 5/2 is still greater than 2
f)
First, let's find out how many moles of water we can get. Since O2 is the limiting reactant, and O2:H2O ratio is 1:2, we will get 4 moles of H2O. Then, we can multiply 4 by Avogadro's number which is
to get the number of molecules. We get: 2.41 * 10^24 molecules of water.