How many atoms are in a solid piece of iron that has a mass of 24.0g?
1 answer:
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Answer: 1. The empirical formula is
2. The molecular formula is
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of P = 37.32 g
Mass of N = 16.88 g
Mass of F = 45.79 g
Step 1 : convert given masses into moles.
Moles of P =
Moles of N =
Moles of F =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For P =
For N =
For F =
The ratio of P: N: F= 1: 1: 2
Hence the empirical formula is
The empirical weight of = 1(31)+1(14)+2(19)= 82.98 g.
The molecular weight = 82.98 g/mole
Now we have to calculate the molecular formula.
The molecular formula will be=