Answer: Option C - Radical
Explanation:
A radical is a chemical specie carrying a lone electron. In the halogenation of alkanes: take Methane CH4 as the alkane, and Chlorine Cl as the halogen.
The step by step halogenation process is as follows:
CH4 + Cl2 --> CH3• + HCl + Cl•
CH3• + Cl2 --> CH3Cl + HCl
CH3Cl + Cl2 --> CH2Cl2 + HCl + Cl•
CH2Cl2 + Cl2 --> CHCl3 + HCl
CHCl3 + Cl2 --> CCl4 + HCl + Cl•
Chlorine molecule attack methane knocking off an hydrogen atom from it and forming a methyl radical (CH3•), that is subsequently attack by another chlorine molecule. This cycle repeats itself, until no hydrogen atom is available for substitution by the highly reactive chlorine radical.
Note: no cation or anion is formed in the halogenation process
Answer:
its burning
Explanation:
can you please try to answer my latest question i need it badly please and thank you
-When Ksp is the solubility product constant for a solid substance when it
dissolved in an aqueous solution, and measure the level at which a solute
dissolves in the solution.
- and we have the solubility and it is the maximum quantity of solute which can dissolve in a certain solute
we can assume the solubility = X = 2.2 x 10^-5 M
and when the balanced reaction equation is:
Mn(OH)2(s) ↔ Mn2+ + 2OH-
∴ the Ksp expression is = [Mn2+] [OH-]^2
when [Mn2+] = X = 2.2 x 10^-5 M
and [OH-] = 2X = 2*(2.2 x 10^-5) = 4.4 x 10^-5 M
by substitution:
∴ Ksp = X * (2X)^2
= (2.2 x 10^-5)(4.4 x 10^-5)^2
= 4.3 x 10^-14
Explanation:
1 mole of a gas has 22.4 L of volume at STP. Therefore, 0.5 mol of H2 has 0.5 x 6.022 x 1023 = 3.011 x 1023 molecules. Hence, the number of moles, molecules and atoms present in 11.2 liters of H2 at STP are 0.5 , 3.011 x 1023 and 6.022 x 1023 respectively.
