The area of a circular sector of central angle α (in radians) in a circle of radius r is given by
... A = (1/2)r²×(α - sin(α))
Your area is expected to be computed as the sum of the areas of a sector with angle π/3 in a circle of radius 8 and a sector with angle π/2 in a circle of radius 6.
... A = (1/2)8²×(π/3 - sin(π/3)) + (1/2)6²×(π/2 - sin(π/2))
... A ≈ 16.07
Radii are in inches so the units of area will be in². The appropriate choice is
... 16.10 in²
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It should be noted that the geometry described is impossible. Chord CD of circle A will have length 6√2 ≈ 8.4853 inches. Chord CD of circle B will have length 8 inches. They cannot both be the same chord.
Answer:
x= 3 inch should be turned up on each side
Step-by-step explanation:
Let the height of trough be x.
Width of trough be 12 - 2x.
and length of trough = 120 inch
Volume of trough, V = L×W×H = 120 × (12-2x) × x = 120x(12 - 2x)
For maximum volume, we find V' = 0
i.e 1440 -480x = 0
or x =
or x= 3
Hence x= 3 inch should be turned up on each side
Answer:

You gave the explicit form.
Step-by-step explanation:
You gave the explicit form.
The recursive form is giving you a term in terms of previous terms of the sequence.
So the recursive form of a geometric sequence is
and they also give a term of the sequence; like first term is such and such number. All this says is to get a term in the sequence you just multiply previous term by the common ratio.
r is the common ratio and can found by choosing a term and dividing by the term that is right before it.
So here r=-3 since all of these say that it does:
-54/18
18/-6
-6/2
If these quotients didn't match, then it wouldn't be geometric.
Anyways the recursive form for this geometric sequence is

I hope everythink is clearly :) If not just ask :)
answer for your question is starting when x^2-14x-95=0. Just Ignore this above this.
Absolute value means the distance from 0.
|-0.45| =0.45
|-0.0045|=0.0045
0.45>0.0045
So
|-0.45|>|-0.0045|