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3 years ago

Acceleration of 10kg Maas's pushed by a 5n force

Mathematics

1 answer:

malfutka [58]3 years ago

7 0

Answer:

<h3>The answer is 0.5 m/s²</h3>

Step-by-step explanation:

To find the acceleration of an object given it's mass and the force acting on it can be found by using the formula

$acceleration = \frac{force}{mass} \\$

From the question

force = 5 N

mass = 10 kg

So we have

$acceleration = \frac{5}{10 } = \frac{1}{2} \\$

We have the final answer as

Hope this helps you

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Help me pls, question is on the picture

Zinaida [17]

Answer:

I just learned this about a few weeks ago I hope this helps.

Step-by-step explanation:

Since it's cosine you're only looking at Adjacent and the hypotenuse which the adj is 20 and the hyp is 25 so since cosine is adj/hyp you do 20/25 then simplify it to 20/25 divide both by 5 so it's simplified to 4/5.

Then you do Cos-1(4/5)=36.869 which is rounded to the tenth 36.9 but rounded to the hundredth 36.87.

Hope this helps

6 0

2 years ago

Pls help I will not let me add the screenshot so I'm going to try and explain. so there is a rectangle the top measures 10m and

-BARSIC- [3]

Answer:

£23

Explanation:

6x10=60
2x1.5=3
3.14x2^2=12.566
60-3-12.566=44.433
44.43/10=4.43
5 bags
5x4.60=23
=£23

3 0

2 years ago

Please help fast. It’s a test

Reil [10]

Were is the question?

6 0

3 years ago

Read 2 more answers

Find the point of intersection of the pair of straight lines Y= -7x - 4 -y = 8x + 9

Aleonysh [2.5K]

Answer:

(-5,31)

Step-by-step explanation:

See image.

4 0

3 years ago

Find the length of UT.

otez555 [7]

Answer: A. 32

Concept:

Here, we need to know the idea of the intersecting chord theorem and segment addition postulate.

The intersecting chord theorem states that when two chords intersect at a point, P, the product of their respective partial segments is equal.

The Segment Addition Postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

Given information

CW = 12

TW = 14

VW = 2x + 5

UW = 2x + 2

Given expression deducted from intersecting chord theorem

CW · VW = TW · UW

Substitute values into the expression

(12) · (2x + 5) = (14) · (2x + 2)

Expand parentheses and apply the distributive property

24x + 60 = 28x + 28

Subtract 14x on both sides

24x + 60 - 24x = 28x + 28 - 24x

60 = 4x + 28

Subtract 28 on both sides

60 - 28 = 4x + 28 - 28

32 = 4x

Divide 4 on both sides

32 / 4 = 4x / 4

x = 8

Given expression deducted from the segment addition postulate

UT = UW + TW

Substitute values into the expression

UT = 2x + 2 + 14

Substitute x value into the expression

UT = 2 (8) + 2 + 14

UT = 16 + 2 + 14

Combine like terms

UT = 32

Hope this helps!! :)

Please let me know if you have any questions

5 0

2 years ago