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telo118 [61]
3 years ago
8

Phil T. Rich has $100 and spends $3 per day. Earnest Worker has only $20 but is adding to it at a

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer: day 11

equation: 100-3d=20+5e

Step-by-step explanation:

do a table. 100-3: 20+5: 97-3:25+5 until you get to the same number. I think that's how you do it. I hope it helps.

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(x-2) is a factor of x^2-3x^2+kx+14. The value of k is?​
BartSMP [9]

Answer:

k = 5

Step-by-step explanation:

I will assume that your polynomial is

x^2 - 3x^2 + kx + 14

If x - a is a factor of this polynomial, then a is a root.

Use synthetic division to divide (x - 2) into x^2 - 3x^2 + kx + 14:

 2      /      1     -3     k     14

                        2     -2    2k - 4

         -------------------------------------

               1        -1    (k - 2)   2k - 10

If 2 is a root (if x - 2 is a factor), then the remainder must be zero.

Setting 2k - 10 = to zero, we get k = 5.

The value of k is 5 and the polynomial is x^2 - 3x^2 + 5x + 14

6 0
3 years ago
The rectangular prism below has a length of 18 inches, a width of 24 inches, and a height of 12 inches.
andrew11 [14]

Answer:

1872

Step-by-step explanation:on edge

3 0
3 years ago
Use the pictures or words to explain how you could find the sum of 7+7
max2010maxim [7]
7+7=14 lol you’re welcome
3 0
2 years ago
Help me please thanks
mars1129 [50]

Answer:

x  <  − 5

The notation would be ( − ∞ ,  − 5 )

On the graph, you would put an open dot on -5 and an arrow continuing down it

7 0
3 years ago
Read 2 more answers
Please answer me question 3 solving part​
Illusion [34]

Answer:

1. D

2. B

3. A

Step-by-step explanation:

Question 1:

The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.

Question 2:

Given that <KLM = x°

<KML = 50°

<JKL = (2x - 15)°

According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.

2x - 15 = x + 50

Solve for x

2x - x = 15 + 50

x = 65

Therefore, <KLM = 65°

QUESTION 3:

<JKL = 2x - 15

Plug in the value of x

<JKL = 2(65) - 15

= 130 - 15

<JKL = 115°

7 0
3 years ago
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