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nikdorinn [45]
3 years ago
8

Which is measured by the power of a machine?

Physics
1 answer:
Alina [70]3 years ago
7 0

the rate of work done or doing work is usually measured by the power of a machine .

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A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 225 kg and it
Orlov [11]

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and sum of forces in bodies.

From Newton's second law we understand that

F= ma (\rightarrow Gravity at this case)

Where,

m = mass

a= acceleration

Also we know that

\rho = \frac{m}{V} \Rightarrow m = \rho V

Part A) The buoyant force acting on the balloon is given as

F_b = ma

As mass is equal to the density and Volume and acceleration equal to Gravity constant

F_b = \rho V g

F_b = 1.2*323*9.8

F_b = 3798.5

PART B) The forces acting on the balloon would be given by the upper thrust force given by the fluid and its weight, then

F_{net} = F_b -W

F_{net} = F_b -(mg+\rho_H Vg)

F_{net} = 3798.5-(9.8*225*9.8*0.179*323)

F_{net} = 1030N

PART C) The additional mass that can the balloon support in equilibrium is given as

F_{net} = m' g

m' =\frac{F_{net}}{g}

m' = \frac{1030}{9.8}

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3 years ago
A battery supplies 0.75 A to three resistors connected in parallel. The current through the first resistor is 0.24 A and the cur
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Total current flow in circuit=0.75
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A man pushes on a piano with mass 190 kgkg ; it slides at constant velocity down a ramp that is inclined at 18.0 ∘∘ above the ho
creativ13 [48]

Answer:

The magnitude of applied force,parallel to the incline is 575.38 N and parallel to the floor is 605 N.

Explanation:

Given:

Mass of the piano (m) = 190 kg

Inclined angle (\theta) = 18 degree

Considering gravity, g = 9.8 ms^-^2

And

Using, sin(18) =0.30 and cos(18)=0.95

<em>FBD diagram is attached with all the force acting on the floor and and the inclined. </em>

We have to find the magnitude of forces,when the man pushes it parallel to the incline and to the floor.

a.

When the man pushes it parallel to the incline.

Balancing the forces as  \sum F=0 .

⇒ F+mgsin(\theta) =0

⇒ F=-mgsin(\theta)

⇒ Here it is negative as the force is acting downward.

⇒ Plugging the values of mass (m) and angle (\theta) .

⇒ F=190\times 9.8\times sin(18)

⇒ F=575.38 N

b.

When the force is parallel to the floor.

⇒ Fcos(\theta)=mgsin(\theta)

⇒ F=\frac{mgsin(\theta)}{cos(\theta)}

⇒ Plugging the values.

⇒ F=\frac{190\times 9.8\times sin(18)}{cos(18)}

⇒ F=605 N

So,

The magnitude of applied force in inclined direction is 575.38 Newton and parallel to the floor is 605 N.

6 0
3 years ago
A football player pushes against another player trying to block him from moving any farther down the field. Which term best desc
Juli2301 [7.4K]

Answer:

its a negative work, not a negative force

Explanation:

I took the quiz first i put negative force i got it wrong

then when i put negative work it was right

Hope it help:)♥︎ plz mark me as brainliest

8 0
3 years ago
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