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alexira [117]
3 years ago
11

Two small plastic spheres each have a mass of 1.2 g and a charge of -56.0 nC . They are placed 3.0 cm apart (center to center).

Part A What is the magnitude of the electric force on each sphere? Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
butalik [34]3 years ago
3 0

Answer:

F_e = +/- 0.013133 N

Explanation:

Given:

- charge on each sphere q = -56 nC

- separation of spheres r = 3.0 cm

- charge constant k = 8.99*10^9

Find:

- Magnitude of Electric Force F_e on each sphere.

Solution:

The magnitude of electric Force F_e of one sphere on other is:

                                F_e = k*q^2 / r^2

- Plugging the given values :

                                F_e = (8.99*10^9) * (56*10^-19)^2 / (0.03)^2

                                F_e = 0.013133 N

- An equal and opposite force is experienced on the other sphere. Hence, F_e = + / - 0.013133 N

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the equation of motion is given for a particle when s is in meters and t is in seconds. Find the acceleration after 4.5 seconds
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Answer:

Explanation:

The question is incomplete.

The equation of motion is given for a particle, where s is in meters and t is in seconds. Find the acceleration after 4.5 seconds.

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dS/dt = 2πcos2πt

d²S/dt² = -4π²sin2πt

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Answer:

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Explanation:

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Second method is very simple

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