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V125BC [204]
3 years ago
14

The temperature of the cosmic background radiation is measured to be 2.7 k. What is the wavelength of the peak in the spectral d

istribution at this temperature?
Physics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer:

1.07\cdot 10^{-3} m

Explanation:

The peak wavelength of the spectral distribution can be found by using Wien's displacement law:

\lambda=\frac{b}{T}

where

b=2.898\cdot 10^{-3} m\cdot K is Wien's displacement constant

T is the absolute temperature

For the cosmic background radiation, the temperature is

T = 2.7 K

So, the corresponding peak wavelength is

\lambda=\frac{2.898\cdot 10^{-3} m\cdot K}{2.7 K}=1.07\cdot 10^{-3} m

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AveGali [126]

Answer:

Explanation:

Using the Condition That Initial Angular Velocity is equal to final angular velocity

total angular momentum is equal to angular momentum of the person + angular Momentum of the PlatformL_{T} = L_{plat} + L_{per}

Note L= I ×ω

Final Angular momentum of the person is equal to the final angular momentum of the platform

Final Moment of Inertia of the person I_{per.f} =mr^{2} =70×(2.7)²=510.3Kgm2

Initial Angular Momentum L_{i} = Final Angular Momentum L_{f}

I_{plat.i} ×ω_{plat.i} +  I_{per.i} ×ω_{per.i} =  I_{plat.f} ×ω_{plat.f}  + I_{per.f} ×ω_{per.f}

890(0.85) + 0 =890(ω_{plat.f}) +510.3(ω_{plat.f})

756.5 = 1400.3 (ω_{plat.f})

(ω_{plat.f}) =0.54rad/s

7 0
3 years ago
A ball is dropped from an upper floor, some unknown distance above your apartment. As you look out of your window, which is 1.50
Lelechka [254]

Answer:1.902 m

Explanation:

Given

height of apartment=1.5 m

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u_1=6.11 m/s

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6.11^2=2\times 9.81\times s

s=\frac{6.11^2}{2\times 9.81}

s=1.902 m

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