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V125BC [204]
3 years ago
14

The temperature of the cosmic background radiation is measured to be 2.7 k. What is the wavelength of the peak in the spectral d

istribution at this temperature?
Physics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer:

1.07\cdot 10^{-3} m

Explanation:

The peak wavelength of the spectral distribution can be found by using Wien's displacement law:

\lambda=\frac{b}{T}

where

b=2.898\cdot 10^{-3} m\cdot K is Wien's displacement constant

T is the absolute temperature

For the cosmic background radiation, the temperature is

T = 2.7 K

So, the corresponding peak wavelength is

\lambda=\frac{2.898\cdot 10^{-3} m\cdot K}{2.7 K}=1.07\cdot 10^{-3} m

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In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

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3 0
3 years ago
Read 2 more answers
An object carries a +15.5 µC charge. It is 0.525 m from a -7.25 µC charge. What is the magnitude of the electric force on the ob
lorasvet [3.4K]

Answer:

the force of attraction between the two charges is 3.55 N.

Explanation:

Given;

first charge carried by the object, q₁ = 15.5 µC

second charge carried by the q₂ = -7.25 µC

distance between the two charges, r = 0.525 m

The force of attraction between the two charges is calculated as;

F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(15\times 10^{-6})(7.25\times 10^{-6})}{(0.525)^2} \\\\F = 3.55 \ N

Therefore, the force of attraction between the two charges is 3.55 N.

3 0
3 years ago
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