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mezya [45]
3 years ago
15

A lawyer owns 4 pairs of pants, 5 dress shirts and 6 ties. How many days can the lawyer go without wearing the same combination

of three items?
Mathematics
2 answers:
Naddik [55]3 years ago
8 0

Answer: 4 × 5 × 6 = 120

Explanation:

1) This is a direct use of the counting principle, which states that the number of different ways a combination of independent events can happen is equal to the product of the number of different outcomes for each event.

That is, if event A can have m different outcomes, event B can have n different outcomes, and event C can have p different outcomes, the total number of different combinations is m × n × p.

2) In this case, the lawyer can use 4 different pais of pants, 5 different shirts, and 6 different ties, so the number of different combinations of the three items is: 4 × 5 × 6 = 120.

3) You can see that if you make a diagram (may be a tree diagram).

With that you can see that each pair of pants, can go with 5 shirts, which make 4 × 5 different couples of pants - shirts. After that, each different couple of pants - shirts can go with 6 different ties, so you have 4 × 5 × 6 three-piece combinations.

RideAnS [48]3 years ago
7 0
6 x 4 x 5 = 120 days

Answer is 120 days.
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Some research suggests that police officers are more likely to make an arrest in the presence of bystanders. If mentally disorde
zmey [24]

Answer:

t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638    

p_v =P(t_{(19)}>1.638)=0.0589    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.    

Step-by-step explanation:

Data given and notation    

\bar X=7.03 represent the sample mean

s=9.42 represent the sample standard deviation    

n=20 sample size    

\mu_o =3.58 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is higher than 3.58 :    

Null hypothesis:\mu \leq 3.58    

Alternative hypothesis:\mu > 3.58    

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638    

P-value    

First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since is a right tailed test the p value would be:    

p_v =P(t_{(19)}>1.638)=0.0589    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.    

7 0
3 years ago
Solve the system of linear equations by graphing y= -x+4 and y= 2x-8 what is the solution
gulaghasi [49]

Answer:

4=x

Step-by-step explanation:

y=-x+4

y=2x-8

-x+4=2x-8

+x       +x

4=3x-8

+8   +8

12=3x

/3   /3

4=x

4 0
2 years ago
The following data summarizes results from 939 pedestrian deaths that were caused by accidents . If one of the pedestrian deaths
olganol [36]

Answer:

Step-by-step explanation:

Hello!

The contingency table is attached.

The total of pedestrians is 909, not 939, there are 30 accidents less in the given data.

I've calculated the asked probabilities using a total of 909.

1. The probability that the pedestrian was intoxicated or the driver was intoxicated.

Two events are mutually exclusive when the occurrence of one prevents the occurrence of the other in one single performance of the experiment. (i.e there is no intersection between the events P(A∩B)=0)

When two events are mutually exclusive, the probability of the union of both elements is equal to the sum of their individual probabilities P(A∪B)= P(A) + P(B).

When the events aren't mutually exclusive, the probability of their union is equal to the summary of their probabilities minus the probability of the intersection between these two events P(A∪B)= P(A) + P(B) - P(A∩B)

Where:

∪ is the union of both events, in colloquial language represents "or"

∩ is the union of both events, or intersection of the events, in colloquial language represents "and"

In this case P(P₁ ∪ D₁) = P(P₁) + P(D₁) - P(P₁ ∩ D₁) = \frac{306}{909} + \frac{132}{909} - \frac{81}{909} = 0.393

P₁ and D₁ are not mutually exclusive

2. The probability of the pedestrian was intoxicated or the driver was not intoxicated.

These two events aren't mutually exclusive.

P(P₁ ∪ D₂)= P(P₁) + P(D₂) - P(P₁ ∩ D₂)= \frac{306}{909} +\frac{777}{909} *-\frac{225}{909}= 0.944

I hope it helps!

3 0
2 years ago
Please quick I need help! Worth 100 POINTS
steposvetlana [31]

Answer:

Step-by-step explanation:

Given the data showing the relationship between GPA and hours of study :

From the regression model given :

Regression equation is:

y = 0.141x + 1.096

Also, the regression Coefficient, R = 0.957

Step-by-step explanation:

a) Describe how the line of best fit and the correlation coefficient can be used to determine the correlation between the two variables on your graph.

From the regression equation, we can infer if the relationship or correlation between the two variables is positive or negative from the value of the slope, a positive slope Value means a positive relationship while a negative slope value means a negative relationship.

The Correlation Coefficient, R also gives the strength of relationship, with values close to - 1 or 1 depicting a strong relationship while positive and negative R values also depictava positive or negative relationship.

Here there is a strong positive relationship between GPA and Hours.

Correlation does not imply causation. Correlation only shows the type of relationship between variables and it does not mean that high GPA values are causes by long hours of study and vice versa

b)

A) The line of best fit gives a general outlook on the data while the correlation is the exact points showcased to calculate or show for a data set or table.

B) Between the two variables it is a positive correlation because they both increase in the same direction. Positive correlation is a relationship between two variables in which both variables move in tandem—that is, in the same direction.

C) Not really considering the fact they are both headed in the same direction. It would if say one was increasing and the other was going in the opposite direction.

D) So, to find the residual I would subtract the predicted value from the measured value

E)

Ex: (Your first row)

9.2 - 2.23 = 6.97

c)

No, we can never tell that correlation is equal to causation. It is a common misconception when looking at data tables.

For instance, if we have a table that shows a correlation of scores on two tests in a row. We may see that there is a correlation between the two numbers. Students who did well on the first test may have done well on the second as well, and those who have not done well on the first may have done poorly on the second.

However, doing bad on the first test does not cause someone to do bad on the second one. Likely the cause is their studying habits, intelligence or aptitude in the area.

So in this example, there is correlation between the sets of data, but it does not prove causation.

d)

A residual is the difference between the observed y-value (from scatter plot) and the predicted y-value (from regression equation line). It is the vertical distance from the actual plotted point to the point on the regression line.

e)

Answer:

the residual is 0

Step-by-step explanation:

The residual is zero because you don't have a trend line. Once you have a trend line the residual is the distance between the y-values(data or dots) and the trend line

f)

The estimated GPA of a student who studies for 15 hours a week is 3.21.

Given:

The table with the GPA of students along with the studying hours of students.

To find:

The residual plot for the given data.

GPA of a student who studies for 15 hours a week.

Solution:

The residual plot of the given data is an image attached.

The equation from the plot:

Where:

x = Hours of studies

y = GPA of student

If the student studies for 15 hours his or her GPA can be estimated as:

The estimated GPA of a student who studies for 15 hours a week is 3.21.

4 0
2 years ago
ABCD is a quadrilateral <br>Work out angle x<br>​
netineya [11]

First of all, we can work out the length of BD: using the pythagorean theorem, we have

BD = \sqrt{6^2+8^2}=10

Now, we can work on triangle BCD and use the sine theorem: we have

\dfrac{BD}{\sin(\hat{C})} = \dfrac{CD}{\sin(x)}

Plugging the values and solving for \sin(x) we have

\dfrac{10}{\sin(29)} = \dfrac{13}{\sin(x)} \iff \sin(x)=\dfrac{13\cdot \sin(29)}{10}\approx 0.63

We deduce

x=\arcsin(0.63)\approx 39

3 0
2 years ago
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