The answer to the question is D
The volume of the metal box if the box was completely solid (V1), is:
V1=(12 inches)³
V1=1728 inches³
As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:
W=12 inches-(3 inchesx2)
W=6 inches
Then, the volumen of the no solid metal box is:
V2=(6 inches)³
V2= 216 inches³
Therefore, the volume of metal needed to smelt the cubical metal box, is:
V3=V1-V2
V3=1728 inches³-216 inches³
V3=1512 inches³
Answer:
x=18
Step-by-step explanation:
4x-10=3x+8
4x-3x
x-10=8
8+10
Answer: <em>10.2</em>
Step-by-step explanation:
<em>Use the Pythagorean Thoerem</em>
The least number of chaperones they will need is 5 chaperones because the greatest amount of students in a group is 4, so less chaperones. If each group has one chaperone that is 5 people per group total. 25 divided by 5 is 5.
