All categories

3 years ago

The impulse given to a ball with mass of 4 kg is 16 N s. If the ball starts from rest, what is its final velocity?

1 answer:

7 0

The formula for impulse is F*(t₂-t₁)=m*(v₂-v₁), where F is the force, t is time, m is mass and v is velocity.

In our case m*(v₂-v₁)=16 N s, m=4 kg, v₁=0 and t₁=0.

m*(v₂-0)=16 N s, we solve for v₂:

4*v₂= 16

v₂=16/4

v₂=4 m/s

So the final velocity of the ball is v₂=4 m/s.

You might be interested in

A mass of 5kg starts from rest and pulls down vertically on a string wound around a disk-shaped, massive pulley. The mass of the

Paha777 [63]

Answer:

c. V = 2 m/s

Explanation:

Using the conservation of energy:

$E_i =E_f$

so:

Mgh = $\frac{1}{2}IW^2 +\frac{1}{2}MV^2$

where M is the mass, g the gravity, h the altitude, I the moment of inertia of the pulley, W the angular velocity of the pulley and V the velocity of the mass.

Also we know that:

V = WR

Where R is the radius of the disk, so:

W = V/R

Also, the moment of inertia of the disk is equal to:

I = $\frac{1}{2}MR^2$

I = $\frac{1}{2}(5kg)(2m)^2$

I = 10 kg*m^2

so, we can write the initial equation as:

Mgh = $\frac{1}{2}IV^2/R^2 +\frac{1}{2}MV^2$

Replacing the data:

(5kg)(9.8)(0.3m) = $\frac{1}{2}(10)V^2/(2)^2 +\frac{1}{2}(5kg)V^2$

solving for V:

(5kg)(9.8)(0.3m) = $V^2(\frac{1}{2}(10)1/4 +\frac{1}{2}(5kg))$

V = 2 m/s

8 0

3 years ago

A 70kg man is moving with a speed of 3.2 m/s on a rough surface, his speed was decreasing uniformly until he reaches to a stop b

VMariaS [17]

Answer:

224 N

Explanation:

6 0

3 years ago

A capacitor is charged to a potential difference of 3 volt it delivers 30% store energy to lamp what is the final potential diff

nexus9112 [7]

Answer:

3.98V

Explanation:

Given

Pontential difference V as 3v

Energy delivered is 30%,

Recall that Enery E=1/2cv^2 from this E=V^2(since Current C is not provided we can assume a value 2)

So E=V^2

E=3^2=9

At full charge E=9,30%of 9,0.3*9=2.7 energy in capacitor is 9-2.7=6.3

But E=V^2

✓E=V

✓6.3=3.98V

4 0

2 years ago

A spacecraft in outer space increases velocity by firing its rockets. How can hot gases escaping from its rockets change the vel

Elena-2011 [213]

Answer:

Momentum is conserved.

Explanation:

-Momentum is conserved.

-By Newton's third law (For every action, there is an equal and opposite reaction.)-the change in momentum of gases in one direction must be balanced by an equal change in momentum of the spacecraft in the opposite direction.

3 0

2 years ago

Newton’s first law says that a body will remain in a state of rest, or move in a straight line at a constant speed, unless it is

dangina [55]

Answer:

Gravity

Explanation:

The Hubble is continually attracted to the earth due to the action of gravity. Therefore, it is thanks to gravity that the space telescope is kept in orbit. Without him, the direct motion generated by inertia would take him out of course. Gravity slows it down and keeps it in the curved path of its orbit around the Earth.

7 0

2 years ago