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3 years ago

The impulse given to a ball with mass of 4 kg is 16 N s. If the ball starts from rest, what is its final velocity?

1 answer:

7 0

The formula for impulse is F*(t₂-t₁)=m*(v₂-v₁), where F is the force, t is time, m is mass and v is velocity.

In our case m*(v₂-v₁)=16 N s, m=4 kg, v₁=0 and t₁=0.

m*(v₂-0)=16 N s, we solve for v₂:

4*v₂= 16

v₂=16/4

v₂=4 m/s

So the final velocity of the ball is v₂=4 m/s.

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If you exert 250J of work onto a lever that is 5m long, what amount of force are you applying?

maks197457 [2]

From the formula of W = F·d , becuase we have the values for W and d we can find F

W = F·d
F= W/d
= 250/5
= 50 N

40 N of force was applied

7 0

3 years ago

Read 2 more answers

Doss [256]

Answer:

The resultant velocity is <u>169.71 km/h at angle of 45° measured clockwise with the x-axis</u> or the east-west line.

Explanation:

Considering west direction along negative x-axis and north direction along positive y-axis

Given:

The car travels at a speed of 120 km/h in the west direction.

The car then travels at the same speed in the north direction.

Now, considering the given directions, the velocities are given as:

Velocity in west direction is, $\overrightarrow{v_1}=-120\ \vec{i}$

Velocity in north direction is, $\overrightarrow{v_2}=120\ \vec{j}$

Now, since $v_1\ and\ v_2$ are perpendicular to each other, their resultant magnitude is given as:

$|\overrightarrow{v_{res}}|=\sqrt{|\overrightarrow{v_1}|^2+|\overrightarrow{v_2}|^2}$

Plug in the given values and solve for the magnitude of the resultant.This gives,

$|\overrightarrow{v_{res}}|=\sqrt{(120)^2+(120)^2}\\\\|\overrightarrow{v_{res}}|=120\sqrt{2} = 169.71\ km/h$

Let the angle made by the resultant be 'x' degree with the east-west line or the x-axis.

So, the direction is given as:

$x=\tan^{-1}(\frac{|v_2|}{|v_1|})\\\\x=\tan^{-1}(\frac{120}{-120})=\tan^{-1}(-1)=-45\ deg(clockwise\ angle\ with\ the\ x-axis)$

Therefore, the resultant velocity is 169.71 km/h at angle of 45° measured clockwise with the x-axis or the east-west line.

4 0

3 years ago

PLEASE HELP ME,, I WOULD BE SO HAPPY

Juliette [100K]

Answer:

Energy is force times distance. For your problem, no matter how long you push, the wall still goes nowhere, so there is no obvious energy transfer. so in conclusion, you actually didn't do anything :(

Explanation:

6 0

3 years ago

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Which event is an example of condensation?

ale4655 [162]

Answer: D

If the fog disappears when the Sun comes out, then this is an example of condensation because:

the Sun actually dries up the fog, and it makes it into higher clouds.

Hope this helps you!

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3 years ago

Explain with one example that different types of organisums live in one habitation

inn [45]

Answer:

When you look at a simple koi pond you can find Koi (the secondary consumer) that feeds off of the zooplankton (first consumer), they eat the phytoplankton (producers). All in a simple food chain

Explanation:

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3 years ago