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3 years ago

The impulse given to a ball with mass of 4 kg is 16 N s. If the ball starts from rest, what is its final velocity?

1 answer:

7 0

The formula for impulse is F*(t₂-t₁)=m*(v₂-v₁), where F is the force, t is time, m is mass and v is velocity.

In our case m*(v₂-v₁)=16 N s, m=4 kg, v₁=0 and t₁=0.

m*(v₂-0)=16 N s, we solve for v₂:

4*v₂= 16

v₂=16/4

v₂=4 m/s

So the final velocity of the ball is v₂=4 m/s.

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The loop is in a magnetic field 0.20 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A

love history [14]

Answer:

Part a)

$EMF = 14 \times 10^{-3} V$

Part b)

$EMF = 15.67 \times 10^{-3} V$

Explanation:

As we know that magnetic flux through the loop is given as

$\phi = B.A$

now we have

$\phi = B\pi r^2$

now rate of change in flux is given as

$\frac{d\phi}{dt} = B(2\pi r)\frac{dr}{dt}$

now we know that

$A = \pi r^2$

$0.285 = \pi r^2$

$r = 0.30 m$

Now plug in all data

$EMF = (0.20)\times 2\pi\times (0.30) \times (0.037)$

$EMF = 14 \times 10^{-3} V$

Part b)

Now the radius of the loop after t = 1 s

$r_1 = r_0 + \frac{dr}{dt}$

$r_1 = 0.30 + 0.037$

$r_1 = 0.337 m$

Now plug in data in above equation

$EMF = (0.20)\times 2\pi\times (0.337) \times (0.037)$

$EMF = 15.67 \times 10^{-3} V$

5 0

3 years ago

Two technicians are discussing service information. Technician A says that online service information is only available from the

Westkost [7]

The correct one is A. Technician Only.
The distribution of service information is regulated by <span>United States Environmental Protection Agency.
According to the rules, all vehicle manufacturers are required to make their service information available for everyone online for 'reasonable prices'.
Because of this, vehicle manufacturers started discontinuing the paper format.</span>

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2 years ago

When you observe a distant galaxy whose photons have traveled for 10 billion years before reaching earth we are seeing that gal?

expeople1 [14]

In reality we don't see the galaxy we see it's reflection .. the light hits or got emitted by the star travel all the way long to hit our eyes .. we see their reflection . everything around you that you see is it's reflection

8 0

3 years ago

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates

34kurt

The given question is incomplete. The complete question is as follows.

A parallel-plate capacitor has capacitance $C_{0}$ = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed $3.00 \times 10^{4}$ V/m?

Explanation:

It is known that relation between electric field and the voltage is as follows.

V = Ed

Now,

Q = CV

or, Q = $C \times Ed$

Therefore, substitute the values into the above formula as follows.

Q = $C \times Ed$

= $8.50 pF \times (\frac{10^{-12} F}{1 pF})(3 \times 10^{4} m/s)(1 mm)(\frac{10^{-3} m}{1 mm})$

= $2.55 \times 10^{-10} C$

Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is $2.55 \times 10^{-10} C$ .

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3 years ago

Chemical properties of an acid include...

Igoryamba

This is a list of well known characteristics of acids:

1) acids increase the concentration of hydronum ions ([H3O+]) when dissolved in water

2) acids taste sour

3) many are corrosive (the higher the acidity the higher the corrosive property)

4) when acids react with some metals produce hydrogen gas

5) acids conduct electricity (due to the presence of hydronium ions)

6) acids neutralize bases

7) acids combine with bases to produce water and salt

8) acids lower the pH of solutions.

They do not feel sticky to the touch. Bases fell slippery but there is not that property of sticky sensation about acids, although some highly concentrated strong acids have high viscosity. You cannot touch highly concentrated strong acids.

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2 years ago

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