All categories

3 years ago

Abishek is a runner. He runs the 100 m sprint

Physics

2 answers:

lions [1.4K]3 years ago

5 0

The answer you are looking for is approximately 1.67 m/s.

Solution/Explanation:

Distance Ran: 100 m.

Time ran: 10x6s, or 60s, or one minute.

Speed: Unknown?

Writing out the formula for speed, using distance and time,

S=D/T.

S=Speed.

D=Distance.

T=Time.

Substituting the given values of the variables,

S=100 m/10x6s, or S=100 m/one minute, or S=100 m/60s.

100÷60=1.6667≈1.67.

So, therefore, the final answer is approximately 1.67 m/s.

I hope that this has helped you. Enjoy your day, and take care.

konstantin123 [22]3 years ago

3 0

Answer:

1.67m/s

Explanation:

Total Distance to be travelled by a Runner=100m

Time Taken=10*6s

Speed=Distance/Time

=100/10*6=10/6=1.67m/s

You might be interested in

A natural atom can be negatively charged by

svet-max [94.6K]

Answer:

By Gaining Electrons

Explanation:

A nuetral atom is negative when it gains electrons, and it can be positive when it loses electrons.

4 0

3 years ago

Read 2 more answers

A robot standing on a cliff shoots a ball upwards with an initial speed of 30 m/s. What is the height of the cliff given that th

valina [46]

Answer:

C 80 m

Explanation:

Given:

v₀ = 30 m/s

a = -10 m/s²

t = 8 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (30 m/s) (8 s) + ½ (-10 m/s²) (8 s)²

Δy = -80 m

The ball lands 80 m below where it started. So the height of the cliff is 80 m.

5 0

3 years ago

Question 2 (10 points)

Simora [160]

Answer:

traping

Explanation:

8 0

3 years ago

Read 2 more answers

In a "Rotor-ride" at a carnival, people rotate in a vertical cylindrically walled "room." If the room radius is 5.5 m, and the r

Crank

Answer:

0.181

Explanation:

We can convert the 0.5 rps into standard angular velocity unit rad/s knowing that each revolution is 2π:

ω = 0.5 rps = 0.5*2π = 3.14 rad/s

From here we can calculate the centripetal acceleration

$a_c = \omega^2r = 3.14^2*5.5 = 54.3 m/s^2$

Using Newton 2nd law we can calculate the centripetal force that pressing on the rider, as well as the reactive normal force:

$F = N = a_cm = 54.3 m$

Also the friction force and friction acceleration

$F_f = N\mu = 54.3 m \mu N$

$a_f = F_f / m = 54.3 \mu$

For the rider to not slide down, friction acceleration must win over gravitational acceleration g = 9.81 m/s2:

$g = a_f = 54.3 \mu$

$9.81 = 54.3 \mu$

$\mu = 9.81 / 54.3 = 0.181$

6 0

3 years ago

Which type of ooze dominates in warm shallow ocean floors?<br>A. Calcareous<br>B. Silieous

gogolik [260]

Actually it's sediment

6 0

3 years ago