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3 years ago

Abishek is a runner. He runs the 100 m sprint

Physics

2 answers:

lions [1.4K]3 years ago

5 0

The answer you are looking for is approximately 1.67 m/s.

Solution/Explanation:

Distance Ran: 100 m.

Time ran: 10x6s, or 60s, or one minute.

Speed: Unknown?

Writing out the formula for speed, using distance and time,

S=D/T.

S=Speed.

D=Distance.

T=Time.

Substituting the given values of the variables,

S=100 m/10x6s, or S=100 m/one minute, or S=100 m/60s.

100÷60=1.6667≈1.67.

So, therefore, the final answer is approximately 1.67 m/s.

I hope that this has helped you. Enjoy your day, and take care.

konstantin123 [22]3 years ago

3 0

Answer:

1.67m/s

Explanation:

Total Distance to be travelled by a Runner=100m

Time Taken=10*6s

Speed=Distance/Time

=100/10*6=10/6=1.67m/s

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Answer:

Magnitude of the resultant force will be 20N in the direction of $F_2$ .

Explanation:

It's given in the question that two forces have been applied on the object given.

Since force is a vector quantity, therefore, it has magnitude and direction both.

$F_1=20N$

$F_2=40N$

Both the forces are in the opposite directions.

Therefore, magnitude of the resultant force of these forces will be,

$F_2-F_1=40-20$

= 20 N

And the direction of the resultant force will be towards $F_2$ .

Therefore, magnitude of the resultant force will be 20N in the direction of $F_2$ .

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3 years ago

Rasheed runs a football 10 meters east, turns and runs the football 6 meters west. If his velocity during this run is found to b

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I believe that would be 48 seconds.

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Question 3 A woman sitting in a stationary car notices a man cycling past her at 40 km/hr. Five seconds after he passes her car,

Naya [18.7K]

The shortest possible distance in which she catches up with the man is 129.7 m.

The given parameters:

speed of the man, v₁ = 40 km/hr

speed of the woman, v₂ = 70 km/hr

time when the woman started moving, t₁ = 5 seconds

To find:

the shortest distance when she catches up with the man

Convert the given speed in km/h to m/s

3.6 km/h = 1 m/s
40 km/h = 40/3.6 = 11.11 m/s
70 km/h = 70/3.6 = 19.44 m/s

Calculate the distance moved by the man before she started following him.

Distance moved by the man = speed x time

= 11.11 m/s x 5 s

= 55.55 m

Let the time the woman catches up with the man = t

Apply the following simple principle to calculate the time.

The man is moving forward and the woman is moving forward to close the gap between them, thus both speeds are working against each other.

$(v_2-v_1)t = 55.55 \ m$

the difference in the speed is because they are working against each other.

$(19.44 - 11.11)t = 55.55\\\\8.33t = 55.55\\\\t = \frac{55.55}{8.33} \\\\t = 6.67 \ s$

The time when the woman catches up with the man = 6.67 s

The shortest distance at which the woman catches up with the man is calculated as;

Shortest distance = woman's speed x time when she catches up

= 19.44 m/s x 6.67 s

= 129.7 m

Thus, the shortest possible distance in which she catches up with the man is 129.7 m.

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3 years ago

Two spherical objects are separated by a distance of 2.59 × 10-3 m. The objects are initially electrically neutral and are very

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Answer:

Number of electrons, n = 12 electron

Explanation:

Given that,

The distance between charged spheres, $d=2.59\times 10^{-3}\ m$

The object experiences an electrostatic force that has a magnitude of, $F=4.94\times 10^{-21}\ N$

The electric force between spheres is given by :

$F=\dfrac{kq^2}{d^2}$

$q=\sqrt{\dfrac{Fd^2}{k}}$

$q=\sqrt{\dfrac{4.94\times 10^{-21}\times (2.59\times 10^{-3})^2}{9\times 10^9}}$

$q=1.91\times 10^{-18}\ C$

Let there are n number of electrons. Using quantization of electric charge we get :

$q=ne$

$n=\dfrac{q}{e}$

$n=\dfrac{1.91\times 10^{-18}}{1.6\times 10^{-19}}$

n = 11.93 electrons

n = 12 electrons

Hence, 12 electrons produce the charge on one of the objects.

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