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3 years ago

Abishek is a runner. He runs the 100 m sprint

Physics

2 answers:

lions [1.4K]3 years ago

5 0

The answer you are looking for is approximately 1.67 m/s.

Solution/Explanation:

Distance Ran: 100 m.

Time ran: 10x6s, or 60s, or one minute.

Speed: Unknown?

Writing out the formula for speed, using distance and time,

S=D/T.

S=Speed.

D=Distance.

T=Time.

Substituting the given values of the variables,

S=100 m/10x6s, or S=100 m/one minute, or S=100 m/60s.

100÷60=1.6667≈1.67.

So, therefore, the final answer is approximately 1.67 m/s.

I hope that this has helped you. Enjoy your day, and take care.

konstantin123 [22]3 years ago

3 0

Answer:

1.67m/s

Explanation:

Total Distance to be travelled by a Runner=100m

Time Taken=10*6s

Speed=Distance/Time

=100/10*6=10/6=1.67m/s

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(a) Neil A. Armstrong was the first person to walk on the moon. The distance between the earth and the moon is . Find the time i

a_sh-v [17]

Answer:

a) It took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.

b) The minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.

Explanation:

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensitie. That radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.

The distribution of the radiation in the electromagnetic spectrum can also be given in wavelengths, but it is more frequent to work with it at frequencies:

Gamma rays

X-rays

Ultraviolet rays

Visible region

Infrared

Microwave

Radio waves.

Any radiation that belongs to electromagnetic spectrum has a speed in vacuum of $3x10^{8}m/s$ .

a) Find the time it took for his voice to reach the Earth via radio waves.

To know the time that took for Neil Armstrong's voice to reach the Earth via radio waves, the following equation can be used:

$c = \frac{d}{t}$ (1)

Where v is the speed of light, d is the distance and t is the time.

Notice that t can be isolated from equation 1.

$t = \frac{d}{c}$ (2)

The distance from the Earth to the Moon is $3.85x10^{8} m$ , therefore.

$t = \frac{3.85x10^{8} m}{3x10^{8}m/s}$

$t = 1.28s$

Hence, it took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.

b) Determine the minimum time that will be required for a message from Mars to reach the Earth via radio waves.

The distance from the Earth to the Mars at its closest approach is $5.76x10^{10}m$ , therefore.

$t = \frac{5.76x10^{10}m}{3x10^{8}m/s}$

$t = 192s$

Hence, the minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.

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3 years ago

Which of the following is characteristic of proficient catching?

uysha [10]

Answer:

The correct answer is option D i.e. A and C

Explanation:

The correct answer is option D i.e. A and C

for proficient catching player must

- learn to absorbed the ball force

- moves the hang according to ball direction to hold the ball

- to catch ball at high height move the finger at higher position

- to catch ball at low height move the finger at lower position

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3 years ago

A ball is at rest at the top of a hill until a boy kicked it with his foot. What is the force that causes motion in this scenari

vazorg [7]

The boy’s foot causes the motion. His foot is the one that causes the ball to roll down the hill.

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2 years ago

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defon

Answer:

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3 years ago

When dots are placed on a page from a laser printer, they must be close enough so that you do not see the individual dots of ink

Dovator [93]

Answer:

y <8 10⁻⁶ m

Explanation:

For this exercise, they indicate that we use the Raleigh criterion that establishes that two luminous objects are separated when the maximum diffraction of one of them coincides with the first minimum of the other.

Therefore the diffraction equation for slits with m = 1 remains

a sin θ = λ

in general these experiments occur for oblique angles so

sin θ = θ

θ = λ / a

in the case of circular openings we must use polar coordinates to solve the problem, the solution includes a numerical constant

θ = 1.22 λ / a

The angles in these measurements are taken in radians, therefore

θ = s / R

as the angle is small the arc approaches the distance s = y

y / R = 1.22 λ / s

y = 1.22 λ R / a

let's calculate

y = 1.22 500 10⁻⁹ 0.42 / 0.032

y = 8 10⁻⁶ m

with this separation the points are resolved according to the Raleigh criterion, so that it is not resolved (separated)

y <8 10⁻⁶ m

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3 years ago