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3 years ago

Abishek is a runner. He runs the 100 m sprint

Physics

2 answers:

lions [1.4K]3 years ago

5 0

The answer you are looking for is approximately 1.67 m/s.

Solution/Explanation:

Distance Ran: 100 m.

Time ran: 10x6s, or 60s, or one minute.

Speed: Unknown?

Writing out the formula for speed, using distance and time,

S=D/T.

S=Speed.

D=Distance.

T=Time.

Substituting the given values of the variables,

S=100 m/10x6s, or S=100 m/one minute, or S=100 m/60s.

100÷60=1.6667≈1.67.

So, therefore, the final answer is approximately 1.67 m/s.

I hope that this has helped you. Enjoy your day, and take care.

konstantin123 [22]3 years ago

3 0

Answer:

1.67m/s

Explanation:

Total Distance to be travelled by a Runner=100m

Time Taken=10*6s

Speed=Distance/Time

=100/10*6=10/6=1.67m/s

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3 years ago

A 3.0 kg box is suspended by a series of ropes as shown below. The tension force in the horizontal rope is -40 N. What is the te

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Explanation:

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The total force in the horizontal and vertical directions must be zero, since the object is at rest and is not accelerating.

The horizontal component of the forces:

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3 years ago

sara and tory are out fishing on the lake on a hot summer day when they both decide to go for a swim. sara dives off the front o

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Here it is an application of Newton's III law

as we know by Newton's III law that every action has equal and opposite reaction

So here as we know that two boys jumps off the boat with different forces

from front side of the boat the boy jumps off with force 45 N which means as per Newton's III law if boy has a force of 45 N in forward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 45 N

Now similar way we can say

from back side of the boat the boy jumps off with force 60 N which means as per Newton's III law if boy has a force of 60 N in backward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 60 N

So here net force due to both jump on the boat is given by

$F_{net} = F_1 - F_2$