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boyakko [2]
3 years ago
10

Simplify each expression.

Mathematics
2 answers:
irga5000 [103]3 years ago
3 0

2 \sqrt{ {m}^{7} }  \\ 6 {n}^{2}  \\ 2x \sqrt[3]{2x}
tino4ka555 [31]3 years ago
3 0

128  \sqrt[3]{m}
Sorry I only know the first one
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Choose the answer that gives both the correct solution and the correct graph.
Anna007 [38]

Answer:

A is the correct answer

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During their first round of golf, Imani was 7 strokes over the party and Peter was 8 strokes below par.
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the integers are positive 7 and negative 8

Step-by-step explanation:


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Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un
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At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

\bf \textit{Periodic Exponential Decay}\\\\
A=I(1 - r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &1013\\
I=\textit{initial amount}\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &0\\
p=period\to &1000
\end{cases}
\\\\\\
1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\
A=I(1- r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &1013\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &t\\
p=period\to &1000
\end{cases}
\\\\\\
A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


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-6 ? I believe so

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because like a number line shows how much you go and when you count the places from 4 to -10 its 6

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