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Lemur [1.5K]
2 years ago
12

(pls help!) What mass of oxygen atoms is required to react completely with 30 u of hydrogen atoms?​

Chemistry
2 answers:
Nataly [62]2 years ago
6 0
  • 2H_2+O_2—»2H_2O

One mole Hydrogen need 1/2mol O_2 .

Moles of Hydrogen

  • 30u/1u
  • 30mol

Moles of O_2

  • 30/2
  • 15mol

Nikolay [14]2 years ago
6 0

\qquad\qquad\huge\underline{{\sf Answer}}

Let's get to the reaction first ~

\qquad \qquad \rm 2H_2 + O_2  \rightarrow 2H_2O

Here, we can infer that if we need 1 mole oxygen gas to react with 2 moles Hydrogen gas.

So, the number of Oxygen gas molecules we need to react should be half the number of Hydrogen gas molecules.

Number of Hydrogen gas molecules is :

\qquad \sf  \dashrightarrow \:  \dfrac{30}{2}

\qquad \sf  \dashrightarrow \:  15

Number of Oxygen gas molecules needed is :

\qquad \sf  \dashrightarrow \:   \dfrac{15}{2}

Number of Oxygen atoms needed :

\qquad \sf  \dashrightarrow \:   \dfrac{15}{2}  \times 2

\qquad \sf  \dashrightarrow \:  {15} \: atoms

One atom of Oxygen weight 16 u, so 15 atoms weight ~

\qquad \sf  \dashrightarrow \:  {15} \times 16

\qquad \sf  \dashrightarrow \:  240 \: u

So, we need 240 u of Oxygen atoms to react completely with 30 u of Hydrogen atoms.

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one method for generating chlorine gas is by reacting potassium permanganate and hydrochloric acid. how many liters of Cl2 at 40
Ronch [10]

<u>Answer:</u> The volume of chlorine gas produced in the reaction is 2.06 L.

<u>Explanation:</u>

  • <u>For potassium permanganate:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of potassium permanganate = 6.23 g

Molar mass of potassium permanganate = 158.034 g/mol

Putting values in above equation, we get:

\text{Moles of potassium permanganate}=\frac{6.23g}{158.034g/mol}=0.039mol

  • <u>For hydrochloric acid:</u>

To calculate the moles of hydrochloric acid, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of HCl = 6.00 M

Volume of HCl = 45.0 mL = 0.045 L   (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

6.00mol/L=\frac{\text{Moles of HCl}}{0.045L}\\\\\text{Moles of HCl}=0.27mol

  • For the reaction of potassium permanganate and hydrochloric acid, the equation follows:

2KMnO_4+16HCl\rightarrow 2MnCl_2+5Cl_2+2KCl+8H_2O

By Stoichiometry of the reaction:

16 moles of hydrochloric acid reacts with 2 moles of potassium permanganate.

So, 0.27 moles of hydrochloric acid will react with = \frac{2}{16}\times 0.27=0.033moles of potassium permanganate.

As, given amount of potassium permanganate is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

16 moles of hydrochloric acid reacts with 5 moles of chlorine gas.

So, 0.27 moles of hydrochloric acid will react with = \frac{5}{16}\times 0.27=0.0843moles of chlorine gas.

  • To calculate the volume of gas, we use the equation given by ideal gas equation:

PV=nRT

where,

P = pressure of the gas = 1.05 atm

V = Volume of gas = ? L

n = Number of moles = 0.0843 mol

R = Gas constant = 0.0820\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 40^oC=[40+273]K=313K

Putting values in above equation, we get:

1.05atm\times V=0.0843\times 0.0820\text{ L atm }mol^{-1}K^{-1}\times 313K\\\\V=2.06L

Hence, the volume of chlorine gas produced in the reaction is 2.06 L.

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Magnesium + lodine<br> What is the resulting chemical formula?
Tju [1.3M]

Answer:

magnesium iodide MgI2

Explanation:

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