Answer:
(Fe(OH)2 + Na2SO4
Explanation:
Iron (II) hydroxide precipitate. Iron (II) hydroxide precipitate (Fe(OH)2) formed by adding few drops of a 1M solution of sodium hydroxide (NaOH) to 0.2 M solution ferrous sulfate (FeSO4). The reaction is FeSO4 + NaOH -> Fe(OH)2 + Na2SO4. This is an example of a double replacement reaction. Pure iron (II) hydroxide is white, however even trace amounts of oxygen make it greenish.
Answer:
Lead atoms have 82 electrons and the shell structure is 2.8. 18.32. 18.4.
Explanation:
The ground state electron configuration of ground state gaseous neutral lead is [Xe].
Answer:
136.5886g of NH3
Explanation:
N2 + 3H2 = 2NH3
The mass of the N2 = 4.01
3H2 has a 2/1 ratio
This means the mass of 3H2 is twice as much as N2.
NH3= 2*N2 = 2*4.01 = 8.02 of NH3
Then, by multiplying the mass by MX (17.031)
8.02*17.031=136.5886g can be produced. Round it if needed.
A= 16.5x100=1650
b=120 divided by 100= 1.2lb
that’s all I know.
