Find the critical value t for the confidence level c= 0.98 and sample size n=7.
1 answer:
Answer:
The critical value is T = 3.143.
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 7 - 1 = 6
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.143.
The critical value is T = 3.143.
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Answer:
9.)
10.)
11.) minutes of calling would make the two plans equal.
12.) Company B.
Step-by-step explanation:
Let <em>t</em> equal the total cost, and <em>m,</em> minutes.
Set up your models for questions 9 & 10 like this:
<em>total cost = (cost per minute)# of minutes + monthly fee</em>
Substitute your values for #9:
Substitute your values for #10:
__
To find how many minutes of calling would result in an equal total cost, we have to set the two models we just got equal to each other.
Let's subtract from both sides of the equation:
Subtract from both sides of the equation:
Divide by the coefficient of , in this case:
__
Let's substitute minutes into both of our original models from questions 9 & 10 to see which one the person should choose (the cheaper one).
Company A:
Multiply.
Add.
Company B:
Multiply.
Add.
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ANSWER
A) -1
EXPLANATION
The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).
That is the average rate of change is:
From the graph, f(0) is 0 and f(4) is -4.
We plug in these values to obtain;
This simplifies to;
Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1
A) -1
EXPLANATION
The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).
That is the average rate of change is:
From the graph, f(0) is 0 and f(4) is -4.
We plug in these values to obtain;
This simplifies to;
Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1