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2 years ago

____ is used to run the best use of the firm's resources, or, perhaps, to determine which products are to be eliminated

Business

1 answer:

AysviL [449]2 years ago

3 0

Product-by-value analysis is the answer. Hope it helps!

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Improving quality seems to be a strategic weapon in gaining market share. However, improving quality entails allocation of resou

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Answer:

A. prevention costs

Explanation:

4 0

2 years ago

You are interested in valuing a 2-year semi-annual corporate coupon bond using spot rates but there are no liquid strips availab

Scorpion4ik [409]

Answer:

Following are the solution to this question:

Explanation:

Assume that $r_1$ will be a 12-month for the spot rate:

$\to 1.25 \% \times \frac{100}{2} \times 0.99 + \frac{(1.25\% \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{100} \times \frac{100}{2} \times 0.99 + \frac{(\frac{1.25}{100} \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{2} \times 0.99 + \frac{(\frac{1.25}{2} +100)}{(1+\frac{r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 0.625 +100)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 100.625)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\$

$\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\\to 0.61875 -98 = \frac{402.5}{(2+r_1)^2}\\\\\to -97.38125= \frac{402.5}{(2+r_1)^2}\\\\\to (2+r_1)^2= \frac{402.5}{ -97.38125}\\\\\to (2+r_1)^2= -4.13\\\\ \to r_1=3.304\%$

Assume that $r_2$ will be a 18-month for the spot rate:

$\to 1.5\% \times \frac{100}{2} \times 0.99+1.5\% \times \frac{100}{2} \times \frac{1}{(1+ \frac{3.300\%}{2})^2}+\frac{(1.5\% \times \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\\to \frac{1.5}{100} \times \frac{100}{2} \times 0.99+\frac{1.5}{100} \times \frac{100}{2} \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{100} \times \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\$

$\to \frac{1.5}{2} \times 0.99+\frac{1.5}{2}\times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{2} +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 0.7425+0.75 \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(0.75 +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1+0.0165)^2}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1.033)}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\$

$\to 1.4925 \times 0.96+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328-97= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to -95.5672= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to (1+\frac{r_2}{2})^3= -1.054\\\\\to r_2=3.577\%$

Assume that $r_3$ will be a 18-month for the spot rate:

$\to 1.25\% \times \frac{100}{2} \times 0.99+1.25\% \times \frac{100}{2} \times \frac{1}{(1+\frac{3.300\%}{2})^2}+1.25\%\times\frac{100}{2} \times \frac{1}{(1+\frac{3.577\%}{2})^3}+(1.25\% \times \frac{\frac{100}{2}+100}{(1+\frac{r_3}{2})^4})=96\\\\$

to solve this we get $r_3=3.335\%$

4 0

2 years ago

The Starr Co. just paid a dividend of $1.85 per share on its stock. The dividends are expected to grow at a constant rate of 4 p

Natasha2012 [34]

Answer:

Explanation:

Last dividend = $1.85 (D0)

growth rate = 4% (g)

Current year dividend (D1) = 1.85*(1+0.04) = $1.924

r = 12%

Current price = D1/(r-g) = 1.924/(0.12-0.04) = 24.05

Price in 3 years = D4/(r-g) = D0*(1+g)^4/(r-g) = 1.85*1.04^4/0.08 = $27.0529792

Price in 14 years = D14/(r-g) = D0*(1+g)^15/(r-g) = 1.85*1.04^15/0.08 = $41.647

7 0

3 years ago

Researchers have found which of these to be the most popular downward influence tactics?

Lerok [7]

The best and most correct answer among the choices provided by the question is the first choice. On the other hand, the answer for the second question is the second choice. I hope my answers has come to your help. God bless and have a nice day ahead!

8 0

2 years ago

A small metal shop operates 10 hours each day, producing 100 parts/hour. If productivity were increased 20%, how many hours woul

ipn [44]

Answer:

The plant would have to work 8.33 hours

Explanation:

Initial productivity:

100 parts were produced in 1 hour

Percentage increase in productivity = 20%

New productivity:

100 + (100 × 0.2) = 100 + 20 = 120

120 parts would be produced in 1 hour

Number of hours the plant would have to work to produce 1000 parts = 1000/120 = 8.33 hours

3 0

2 years ago