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alexdok [17]
3 years ago
15

A prescription medication requires 5.98 mg per kg of body weight.

Chemistry
1 answer:
valkas [14]3 years ago
5 0

<u>Answer:</u>

<u>For A:</u> The 0.0132 grams is required per pound of the body weight.

<u>For B:</u> The dost required for 191 lb patient is 5.96 grams.

<u>Explanation:</u>

  • <u>For A:</u>

We are given:

Medication requirement = 5.98 mg/kg

To convert the given amount in grams per pounds, we use the conversion factor:

1 kg = 2.20462 lb

1 g = 1000 mg

Converting the value into grams per pounds, we get:

\Rightarrow (\frac{5.98mg}{kg})\times (\frac{1g}{1000mg})\times (\frac{2.20462lb}{1kg})\\\\\Rightarrow 0.0132g/lb

Hence, the 0.0132 grams is required per pound of the body weight.

  • <u>For B:</u>

To calculate the amount of medication for 191 lb patient, we use unitary method:

For 1 lb body weight, the amount required is 0.0132 grams.

So, for 191 lb body weight, the amount required is \frac{0.0312g}{1lb}\times 191lb=5.96g

Hence, the dost required for 191 lb patient is 5.96 grams.

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Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed  or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

ΔT  = 39°C - 22°C = 17°C

Heat absorbed by the copper :

Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

5 0
3 years ago
When a 5.00-g metal piece, A, was immersed in 38.0 mL of water, the water level rose to 50.0 mL. Similarly, when a 5.00-g metal
Mnenie [13.5K]

Answer:

A is denser than B as it's volume for the same mass is smaller.

Explanation:

Hello.

In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:

V_A=50.0mL-38.0mL=12.0mL\\\\V_B=60.0mL-38.0mL=22.0mL

Next, we compute the densities as shown below:

\rho_A=\frac{m_A}{V_A}=\frac{5.00g}{12.0mL}=0.42g/mL\\  \\\rho_B=\frac{m_B}{V_B}=\frac{5.00g}{22.0mL}=0.23g/mL

In such a way, A is denser is B as it's volume for the same mass is smaller.

Best regards.

4 0
3 years ago
3. Matter with a composition that is always the same is a(n)<br> substance<br> mixture<br> compound
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Answer:

substance

Explanation:

A pure substance is a form of matter that has a constant composition (meaning it's the same everywhere) and properties that are constant throughout the sample (meaning there is only one set of properties such as melting point, color, boiling point, etc

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3 years ago
Ammonia gas decomposes to form nitrogen and hydrogen gases. NH3(g) → N2(g) 3H2(g) If the nitrogen gas is collected in a rigid 2
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Decomposition is a chemical reaction that breaks the reactant into two or more products. Moles of nitrogen gas (\rm N_{2}) in the cylinder is 1.63 moles.

<h3>What is the ideal gas equation?</h3>

The ideal gas equation states the relation of the hypothetical ideal gas according to the pressure, volume, temperature and moles of the gas. It is given by,

\rm PV = nRT

Where,

Pressure (P) = 2000 kPa

Volume (V) = 2L

Temperature (T) = 295 K

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Substituting values  in the equation:

\begin{aligned} \rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{2000 \times (\dfrac{1}{101.325}) \times 2}{0.08206 \times 295}\\\\&= 1.63\;\rm mol\end{aligned}

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Learn more about ideal gas equation here:

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6 0
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qaws [65]

Answer:

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Explanation:

Elements are placed into different groups in the periodic table. Elements in the same group are those that have the same number of valence electrons in their outermost shell and as a result will behave similar chemically i.e. will react with other elements in the same manner.

Chlorine and Bromine are two elements belonging to group 7 of the periodic table. They are called HALOGENS and they have seven valence electrons in their outermost shell. Hence, when they form a compound with Calcium, a group two element, these compounds (CaCl2 and CaBr2) will possess similar properties because they have elements that are from the same group (halogen group).

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