Answer:
Q = 1.68 Kcal
Explanation:
∴ m H2O = 12.0 g
∴ T1 = 35°C ≅ 308 K
∴ T2 = 175°C ≅ 448 K
∴ ΔT = T2 - T1 = 175 - 35 = 140 °C
∴ Cp H2O = 1 cal /g.°C
⇒ Q = (12.0 g)(1 cal/g°C)(140 °C)
⇒ Q = (1680 cal)*(Kcal/1000 cal)
⇒ Q = 1.68 Kcal
When iron rusts and forms iron oxide, the iron oxide has more mass than the iron because there are more iron atoms in iron oxide than in pure iron.
The process of rust occurs when pure iron is exposed to air and moisture. Rust is the oxidation of pure iron to iron II oxide (Fe2O3).
We can see that there are two iron atoms per mole of Fe2O3 whereas there is only one iron atom in each mole of pure iron.
Therefore, iron oxide has more mass than the iron because there are more iron atoms in iron oxide than in pure iron.
Learn more; brainly.com/question/18376414
Answer:
4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.
Explanation:
By ideal gas equation:
Number of moles (n)
can be written as: 
where, m = given mass
M = molar mass
where,
which is known as density of the gas
The relation becomes:
.....(1)
We are given:
M = molar mass of chloroform= 119.5 g/mol
R = Gas constant = 
T = temperature of the gas = 
P = pressure of the gas = 1.00 atm
Putting values in equation 1, we get:
4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.
Because The bar would become negatively charged and repel the metal ball. A magnetic north pole would be generated on the bar, and it would repel the metal ball.
BaO, Barium Oxide.
Na2SO4, Sodium Sulfate.
CuO, Copper (II) Oxide.
P2O5, Diphosphorus Pentoxide.
HNO3, Nitric Acid.
CO32-, Molecular Formula.
Hope this helps. :)
