All categories

3 years ago

HNO3 Express your answers as ions separated by a comma.

1 answer:

4 0

In this item, it is assumed that we are to express the given compound in their ionic form. To be able to determine as to what ions this compound will dissociate into, we have the chemical reaction.

HNO3 --> H⁺ + NO₃⁻

Hence, the ions are H⁺, NO₃⁻.

You might be interested in

4. Which change to a DNA molecule would have the least effect on an organism?

Sav [38]

Answer: Change in a single nitrogen base in the DNA sequence will not have any significant effect on the organism.

So A

Explanation:

This is known as point mutation and it does not have any significant change in the protein and it is least harmful type of DNA mutation.

5 0

3 years ago

Explains how commercial land use negatively impacts watersheds?

Juli2301 [7.4K]

Polluted water. The growing crops and climate variability change. Basically the farming

3 0

3 years ago

If you trace back the history of a carbon atom in your little finger through all of cosmic history, where did this atom most lik

Kamila [148]

Answer:

It was fused from 3 helium nuclei in the core of a red giant star long before the Sun existed

Explanation:

8 0

2 years ago

Substance in mixtures do not change chemically. True or false

AnnZ [28]

Answer:

find the answer elsewhere

Explanation:

8 0

3 years ago

If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically

Phantasy [73]

548.55 grams of aluminum hydroxide should theoretically form.

Explanation:

Balanced equation for the reaction:

3 NaOH + Al ⇒ Al(OH)3 +3 Na

DATA GIVEN:

mass of NaOH = 842 grams, atomic mass =39.9 grams/mole

mass of Al = 750 grams, atomic mass = 26.9 grams/mole

aluminum hydroxide theoretical yield = ?

Moles of NaOH reacted

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the equation

NaOH = $\frac{842}{39.9}$

= 21.1 MOLES OF NaOH

Al = $\frac{750}{26.9}$

= 27.8 moles

from the equation

from 3 moles of NaOH 1 mole of Al(OH)3 is produced

21.1 moles of NaOH will react to give x moles of Al(OH)3

$\frac{1}{3}$ = $\frac{x}{21.1}$

7.03 moles of Al(OH)3 is formed.

and

1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction

so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH

mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)

= 548.55 grams

theoretical yield from the given data is 548.55 grams

3 0

3 years ago