Answer:
The answer to your question is 15500 mg of MgSO₄ 7H₂O
Explanation:
Data
Volume = 30 ml
Concentration = 0.3 M
Formula MgSO4∗7H2O
Process
1.- Calculate the number of moles needed
Molarity = moles / volume
Solve for moles
moles = Molarity x volume
Substitution
moles = 0.3 x 0.03 l
moles = 0.009 moles of MgSO₄
2.- Calculate the molecular mass of MgSO4∗7H2O
molecular mass = 24 + 32 + 64 + 14 + 112
= 246 g
3.- Get the proportion MgSO4 :7H2O, this proportion is 1 : 7
4.- Calculate the amount of MgSO4∗7H2O
Simplification
15.5 g = 15500 mg
Answer:
Iterate to improve the solution
Explanation:
apex
The answer is 2 electrons.
The electron configuration of calcium is 2:8:8:2
Calcium has two electrons in its outermost shell. These are its valence electrons and are the ones used in bonding with other elements. Valence electrons of an atom are those electrons that are in its outer energy shell or that are available for bonding.
Calcium is a metal. When metals react with non-metals, electrons are transferred from the metal atoms to the non-metal atoms forming ions. The resulting compound is known as an ionic compound.
For example, when calcium metal reacts with chlorine gas, calcium gives up its two valence electrons and Chlorine accepts them resulting in a new substance called calcium chloride in which the two elements have ended up forming ionic bonds.
