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Pavlova-9 [17]
3 years ago
9

How would you simplify (3+i)(4+2i)?​

Mathematics
2 answers:
const2013 [10]3 years ago
7 0

Answer:

<h2>(3 + i)(4 + 2i) = 10 + 10i</h2>

Step-by-step explanation:

Use FOIL: (a + b)(c + d) = ac + ad + bc + bd

and i² = -1

(3+i)(4+2i)\\\\=(3)(4)+(3)(2i)+(i)(4)+(i)(2i)\\\\=12+6i+4i+2i^2\qquad\text{combine like terms}\\\\=(12-2)+(6i+4i)\\\\=10+10i

Lunna [17]3 years ago
7 0

Answer:

11 + 10i

Step-by-step explanation:

Note that we're multiplying two binomials here, and thus may use the FOIL method.  This requires four multiplications, as follows:

3*4 + 3*2i + 4i - 1               (The last term is 1 because i(i) = i^2 = -1.)

Simplifying, we get:

12 + 6i + 4i -1, or:

11 + 10i

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