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masha68 [24]
3 years ago
13

Graph the function f(x) = 2 √ X +3

Mathematics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Find the domain for  

y

=

√

x

−

3

+

2

y=x-3+2

so that a list of  

x

x

values can be picked to find a list of points, which will help graphing the radical.

Tap for more steps...

[

3

,

∞

)

[3,∞)

{

x

|

x

≥

3

}

{x|x≥3}

To find the radical expression end point, substitute the  

x

x

value  

3

3

, which is the least value in the domain, into  

f

(

x

)

=

√

x

−

3

+

2

f(x)=x-3+2

.

Tap for more steps...

2

2

The radical expression end point is  

(

3

,

2

)

(3,2)

.

(

3

,

2

)

(3,2)

Select few  

x

x

values from the domain. It would be more useful to select the values so that they are next to the  

x

x

value of the radical expression end point.

Tap for more steps...

x

y

3

2

4

3

5

3.41

xy324353.41

Step-by-step explanation:

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A barrel of tomato sauce has spilled on a tile floor. The sauce flow can be expressed with the function r(t) = 2t, where t repre
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<span>This gives </span>
<span>d A/ d t = 2 pi 2t 2 d t = 8 pi t dt </span>
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Rachel babysits the Michaelson’s kids on Saturdays for 4 hours and is paid $12.50 per hour. On Sundays, she babysits at the Smit
NeTakaya

Answer:

She earns $8.00 more on Sunday

Step-by-step explanation:

Saturday 12.50x4=50.00

Sunday 14.50x4=58.00

5 0
3 years ago
White and black shapes are used in a game Some of the shapes are circles All the other shapes are squares The ratio of white to
PIT_PIT [208]

Answer:

The fraction of all shapes which are square in shape is \frac{23}{32}.

Step-by-step explanation:

Given that , in a game , white and black shapes are used. Some of them are circle in shape and remains are square in shape.

The ratio of white to black shapes are 5:11.

Consider 5x= the number of shapes which are white in color.

11x= The number of shapes which are black in color.

There are (5x+11x)= 16x shapes in the game.

The  white circle and white square are in the ratio 3:7.

The number of white square is

=(\textrm{The number of white shape})\times (\frac{7}{3+7})

=(5x)\times (\frac{7}{10})

=\frac{7x}{2}

The black circles and black square are in the ratio 3:8

The number of black square is

=(\textrm{The number of black shape})\times (\frac{8}{3+8})

=(11x)\times (\frac{8}{11})

=8x

Therefore the total number of shape which are square is

=\frac{7x}{2}+8x

=\frac{7x+16x}{2}

=\frac{23x}{2}

The fraction of all shape are square is

=\frac{\textrm{shape in square}}{\textrm{Total number shape}}

=\frac{\frac{23x}{2}}{16x}

=\frac{23}{32}

5 0
4 years ago
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
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