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masha68 [24]
3 years ago
13

Graph the function f(x) = 2 √ X +3

Mathematics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Find the domain for  

y

=

√

x

−

3

+

2

y=x-3+2

so that a list of  

x

x

values can be picked to find a list of points, which will help graphing the radical.

Tap for more steps...

[

3

,

∞

)

[3,∞)

{

x

|

x

≥

3

}

{x|x≥3}

To find the radical expression end point, substitute the  

x

x

value  

3

3

, which is the least value in the domain, into  

f

(

x

)

=

√

x

−

3

+

2

f(x)=x-3+2

.

Tap for more steps...

2

2

The radical expression end point is  

(

3

,

2

)

(3,2)

.

(

3

,

2

)

(3,2)

Select few  

x

x

values from the domain. It would be more useful to select the values so that they are next to the  

x

x

value of the radical expression end point.

Tap for more steps...

x

y

3

2

4

3

5

3.41

xy324353.41

Step-by-step explanation:

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Please help me with this problem. I am not sure if I am correct.
jek_recluse [69]

Answer:

only -7

Step-by-step explanation:

Just plug them in.

so for x=-7 \sqrt{-2(-7)-5}=(-7)+4\\\sqrt{9}=-3 \\ 3=-3So this one is extraneous

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How do you do <br>this <br><br>(move 3 circles to make the figure upside down
velikii [3]

Answer:

Move the top left and right to the sides of the second to last row, then move the single circle from the bottom row to the top.

Step-by-step explanation:

8 0
3 years ago
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8 0
2 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
leonid [27]

Answer:

\boxed {\boxed {\sf d\approx 4.2}}

Step-by-step explanation:

The formula for distance is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Where (x₁, y) and (x₂, y₂) are the points.

We are given (-6, 6) and (-3, 3). If we match the value and its corresponding variable, we see that:

  • x₁= -6
  • y₁ = 6
  • x₂ = -3
  • y₂ = 3

Substitute the values into the formula.

d= \sqrt{ (-3 - -6)^2+(3-6)^2

Solve inside the parentheses.

  • -3 --6 = -3+6 = 3
  • 3-6 = -3

d= \sqrt{(3)^2+ (-3)^2

Solve the exponents.

  • (3)²= 3*3= 9
  • (-3)²= -3*-3 =9

d= \sqrt{9+9

Add.

d= \sqrt18

d= 4.24264069

Round to the nearest tenth. The 4 in the hundredth place tells us to leave the 2 in the tenth place.

d \approx 4.2

The distance between the two points is apprximately <u>4.2</u>

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