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nata0808 [166]
3 years ago
15

Rank the following steps involved in preparing a dilute solution from a stock solution in order from first to last.

Chemistry
1 answer:
Serggg [28]3 years ago
5 0

Answer: C - B - A - D

Explanation:

-Obtain a flask that is thoroughly cleaned

-Add the desired amount of stock solution

-Add deionized water until the volume reaches the mark on the flask.

- Cap the flask and invert several times to thoroughly mix the solution.

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Convert 912 mmhg to kpa
tatyana61 [14]
The answer is <span>121.59 
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4 years ago
A 1.00 liter solution contains 0.42 moles nitrous acid and 0.32 moles sodium nitrite .
xeze [42]

Answer:

E. The ratio of [HNO2] / [NO2-] will increase

D. The pH will decrease.

Explanation:

Nitrous acid ( HNO₂ ) is a weak acid and NaNO₂ is its salt . The mixture makes a buffer solution .

pH = pka + log [ salt] / [ Acid ]

= 3.4 + log .32 / .42

= 3.4 - .118

= 3.282 .

Now .16 moles of nitric acid is added which will react with salt to form acid

HNO₃ + NaNO₂ = HNO₂ + NaNO₃

concentration of nitrous acid will be increased and concentration of sodium nitrite ( salt will decrease )

concentration of nitrous acid = .42 + .16 = .58 M

concentration of salt = .32 - .16 = .16 M

ratio of [HNO₂ ] / NO₂⁻]

= .42 / .32 = 1.3125

ratio of [HNO₂ ] / NO₂⁻] after reaction

= .42 + .16 / .32 - .16

= 58 / 16

= 3.625 .

ratio will increase.

Option E is the answer .

pH after reaction

= 3.4 + log .16 / .58

= 2.84

pH will decrease.

4 0
3 years ago
There are around muscles in the human body<br><br> 640<br> 250<br> 100
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There are 640 muscles in the human body
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4 years ago
1. A group of elements that includes the most active of the nonmetals is the
Sunny_sXe [5.5K]

Answer:

D. Halogens

Explanation:

All elements in these groups have 7 valence electrons, meaning their electronegativity is the highest among the elements.

4 0
3 years ago
How many grams of sodium azide are required to form 16.55g of nitrogen gas in
MrRissso [65]

Answer:

16.8128 grams of sodium azide is needed

Explanation:

2NaN3 = 2Na + 3N2

molar mass of NaN3 =

2(11 + (7  \times 3) = 64

molar mass of N2

3(7 \times 2) = 42

moles of N2 =

moles=mass/R.F.M

16.55÷42 = 0.3940

mole ratio=

2NaN3 : 3N2

3 = 0.3940

2=?

0.394. \times 2 \div 3 = 0.2627

Mass of sodium azide =64×0.2627

=16.8126

6 0
3 years ago
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