Answer:
Explanation:
Let's try and figure out the ones you don't keep.
Receipts from the dollar tree. You can't return what you bought and you only paid a dollar. It's not worth it.
Food receipts. You can't return it and unless you want to itemize what you spend / month and on what, they don't serve any purpose.
Now figure out which ones you would want to keep
1. Anything pertaining to medical perscriptions. I don't know how it works in the United States, but in Canada we are allowed to deduct only medications with a DIN number.
2 Anything that you would use for travelling that is not for pleasure (ie it is a business expense). So if you are a salesman and your territory is from A to B you would deduct meals, mileages, motels if you must stay away from home
3 In the states some tax receipts are deductible, so you might want to save those.
Answer:
N2O2(g) +O2(g) ===> 2NO2(g)
Explanation:
For a nonelementary reaction, the reaction equation is described as the sum of all the steps involved. All these steps constitute the reaction mechanism. Each step in the mechanism is an elementary reaction. The rate law of the overall reaction involves the rate determining step (slowest step) in the reaction sequence.
Now look at the overall reaction 2NO(g) + O2(g) ---------> 2NO2(g)
The two steps in the mechanism are
2NO(g) --------->N2O2(g) (fast)
N2O2(g) +O2(g) -------> 2NO2(g) (slow)
Summing all the steps and cancelling out the intermediate N2O2(g), we obtain the reaction equation;
2NO(g) + O2(g) ---------> 2NO2(g)
Hence the answer.
Answer:
i cant see the photo but i would love to help
Explanation:
The chemical reaction would be:
C3H8 + 5O2 = 3CO2 + 4H2O
For this case, we assume that gas is ideal thus in every 1 mol the volume would be 22.41 L. We calculate as follows:
28.7 L C3H8 ( 1 mol / 22.41 L ) ( 4 mol H2O / 1 mol C3H8 ) ( 18.02 g / mol ) = 92.31 g H2O produced
Hope this answers the question.
The strength of an Arrhenius base determines percentage of ionization of base and the number of OH⁻ ions formed.
Strong base completely ionize in water and gives a lot of hydroxide ions (OH⁻), for example sodium
hydroxide: NaOH(aq) → Na⁺(aq)
+ OH⁻(aq).
Weak base partially ionize in water and gives a few hydroxide ions (OH⁻), for example ammonia: NH₃ + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq).
