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2 years ago

What is not brought into equilibrium when entropy increases?

Chemistry

1 answer:

saveliy_v [14]2 years ago

3 0

Available energy for work is not brought into equilibrium when entropy increases

The entropy of a system ( isolated ) will continue to increase until the system attains equilibrium. but as the entropy increases the available useful energy for work will decrease making some initially available energy to be become unavailable.

The entropy increases until a system(s) will be brought into equilibrium but the available/transferred energy is not brought into equilibrium instead available energy continues to decrease as entropy increases towards equilibrium.

Hence we can conclude that Available energy is not brought into equilibrium when entropy increases

Learn more : brainly.com/question/2722633

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Have you had the chance to watch a tree grow over a span of several years? Did you notice that the tree grew thicker and taller?

Kruka [31]

Explanation:

All of the cells would be identical.

is correct answer

3 0

2 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.71 g of ethane is

DanielleElmas [232]

Answer:

Explanation:

Step 1:

The balanced equation for the reaction between gaseous ethane and gaseous oxygen. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Step 2:

Determination of the masses of C2H6 and O2 that reacted and the mass of CO2 produced from the balanced equation. This is illustrated below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

Mass of C2H6 from the balanced equation = 2 x 30 = 60g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 7 x 32 = 224g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 4 x 44 = 176g

From the balanced equation above,

60g of C2H6 reacted with 224g of O2 to produce 176g of CO2.

Step 3:

Determination of the limiting reactant.

We need to determine the limiting reactant as it will be needed to obtain the maximum mass of CO2.

From the balanced equation above,

60g of C2H6 reacted with 224g of O2.

Therefore, 2.71g of C2H6 will react with = (2.71 x 224)/60 = 10.12g of O2.

From the above calculation, we can see that a higher mass of O2 is needed to react with 2.71g of C2H6, therefore, O2 is the limiting reactant.

Step 4:

Determination of the maximum mass of CO2 produced when 2.71 g of ethane is mixed with 7.6 g of oxygen.

The limiting reactant is used to determine the maximum mass.

From the balanced equation above,

224g of O2 produce 176g of CO2.

Therefore, 7.6g of O2 will produce = (7.6 x 176)/224 = 5.97g ≈ 6g of CO2

From the calculations made above, the maximum mass of CO2 produced is 5.97 ≈ 6g

5 0

3 years ago

Each enzyme functions in a different area of the body, but both work to harness the power in carbohydrates and break these compl

Whitepunk [10]

The optimal pH is 6.9. The pancreatic amylase is a hydrolase secreted by pancreas and will go into the alimentary canal. The working environment has a pH of 6.9. So the optimal pH for the enzyme needs to be 6.9.

5 0

3 years ago

Read 2 more answers

What volume of a 0. 100mhcl stock solution should be used to prepare 250. 00ml of 0. 0250mhcl?.

Alex_Xolod [135]

62.5 mL is prepare .

What is molarity?

Molar concentration is a unit of measurement for the concentration of a chemical species, specifically a solute, in a solution, expressed as the amount of substance per unit volume of solution. The most often used unit for molarity in chemistry is the number of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units.

Molarity of the stock solution as 0.100 M

Volume of the dilute solution as 250 mL

Molarity of dilute solution as 0.0250 M

We are required to calculate the Volume of the stalk solution.

Taking the volume and molarity of the stock solution to be V₁ and M₁ respectively, and volume and molarity of the dilute solution to be V₂ and M₂ respectively.

We are going to use the dilution formula;

According to the dilution formula, M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

= (0.025 M × 0.25 L) ÷ 0.100 M

= 0.0625 L

But, 1 L = 1000 mL

V₁ = 62.5 mL

Therefore, the volume of the stock solution is 62.5 mL

Learn more about molarity from given link

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3 0

1 year ago

Is a forward or reverse reaction favored?

Alex Ar [27]

Answer:

(a) $CH_3COOH \rightleftharpoons CH_3COO^-+ H^+$ : reverse reaction is favored.

(b) $AgCl \rightleftharpoons Ag^+ + Cl^-$ : reverse reaction is favored.

(d) $A+B\rightleftharpoons C$ : forward reaction is favored.

Explanation:

Hello,

(a) $CH_3COOH \rightleftharpoons CH_3COO^-+ H^+$ :

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (acetic acid) will tend to have a higher concentration.

(b) $AgCl \rightleftharpoons Ag^+ + Cl^-$ :

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (silver chloride) will tend to have a higher concentration.

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (aluminium hydroxide) will tend to have a higher concentration.

(d) $A+B\rightleftharpoons C$

In this case, since the Ka is greater than 1, we infer the forward reaction is favored since the product (C) will tend to have a higher concentration.

Regards.

6 0

3 years ago