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3 years ago

In the diagram shown, what is occurring at the section marked 4?

Chemistry

1 answer:

astra-53 [7]3 years ago

4 0

You need to show an image of the diagram or else nobody knows what you’re referring to.

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3 years ago

which statement regarding the relative energies of monochromatic light with with λ = 800 nm andmonochromatic light with λ = 400

olga2289 [7]

Answer:

The correct answer is option A.

Explanation:

Energy of the photon of an electromagnetic radiation is give by Planck's equation:

$E=\frac{hc}{\lambda }$

Where:

h = Planck's constant

c = speed of light

$\lambda$ = Wavelength of the photon's radiation

Energy of photon of 800 nm monochromatic light

$\lambda = 800 nm=400\times 10^{-9} m$

$E=\frac{hc}{800 \times 10^{-9} m}$

Energy per mole of photons:

$E\times N_A=\frac{hc}{800 \times 10^{-9} m}\times 6.022\times 10^{23} mol^{-1}$ ..[1]

Energy of photon of 400 nm monochromatic light

$\lambda '= 400 nm=400\times 10^{-9} m$

Energy per mole of photons:

$E'\times N_A=\frac{hc}{400 \times 10^{-9} m}\times 6.022\times 10^{23} mol^{-1}$ ..[2]

[1] ÷ [2]

$\frac{E\times N_A}{E'\times N_A}=\frac{\frac{hc\trimes 6.022\times 10^{23} mol^{-1}}{800 \times 10^{-9} m}}{\frac{hc\times 6.022\times 10^{23} mol^{-1}}{400 \times 10^{-9} m}}$

$\frac{E}{E'}=\frac{1}{2}$

$E=\frac{1}{2}\times E'$

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