N = 3.2 moles, T = 50 + 273 = 323 K, P = 101.325 kPa, R = 8.314 L.kPa/K.mol
PV = nRT
V = nRT / P substituting.
V = (3.2 mole)(8.314 L.kPa/K.mol )(323 K) / (<span>101.325 kPa)
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Answer:
B.
Converted to renewable ones
exhausted or depleted
Answer:
The new pressure of the gas comes out to be 400 KPa.
Explanation:
Initial volume of gas = V = 
Initial pressure of gas = P = 120 KPa
Final volume of gas = V' = 
Assuming temperature to be kept constant.
Assuming final pressure of the gas to be P' KPa
New pressure of gas = 400 KPa
Answer:
Nitrogen
Oxygen
Argon
Carbon Dioxide
Methane
Ozone
Explanation:
N₂ accounts for 78% of the atmosphere.
O₂ accounts for 21% of the atmosphere.
Ar accounts for 0.9% of the atmosphere.
CO₂, CH₄, and O₃ only take up 0.1% of the atmosphere.
