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chubhunter [2.5K]

2 years ago

12

Select the most likely product for this reaction: upper a g upper n upper o subscript 3 (a q) plus upper n a upper o upper h (a

q) right arrow question mark. agoh(s) nano3(aq) ag2o(s) hno3(aq) ag(s) h2(g) o2(g)

2 answers:

Mamont248 [21]2 years ago

5 0

One of the most likely products for the reaction would be $Ag_2O$

<h3>Chemical reactions</h3>

The reaction between $AgNO_3$ and $NaOH$ yields 3 products which are $Ag_2O$ (a precipitate), $NaNO_3$ , and $H_2O$ as shown by the equation below:

$2 AgNO_3 + 2 NaOH --- > Ag_2O + 2 NaNO_3 + H_2O$

One of the products precipitates out of the solution to give the reaction a precipitation reaction look.

More on precipitation reaction can be found here: brainly.com/question/24158764

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pav-90 [236]2 years ago

3 0

The products of this reaction are H2O + NaNO3 + Ag2O.

<h3>What is a reaction?</h3>

The term reaction has to do with the combination of two or more substances to yiled product(s).

In this case, we have the reaction; AgNO3 + NaOH, the products of this reaction are H2O + NaNO3 + Ag2O.

Learn more about reaction:brainly.com/question/17434463

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You might be interested in

A strontium hydroxide solution is prepared by dissolving 10.60 gg of Sr(OH)2Sr(OH)2 in water to make 47.00 mLmL of solution.What

NeTakaya

Answer:

Approximately $1.854\; \rm mol\cdot L^{-1}$ .

Explanation:

Note that both figures in the question come with four significant figures. Therefore, the answer should also be rounded to four significant figures. Intermediate results should have more significant figures than that.

<h3>Formula mass of strontium hydroxide</h3>

Look up the relative atomic mass of $\rm Sr$ , $\rm O$ , and $\rm H$ on a modern periodic table. Keep at least four significant figures in each of these atomic mass data.

$\rm Sr$ : $87.62$ .
$\rm O$ : $15.999$ .
$\rm H$ : $1.008$ .

Calculate the formula mass of $\rm Sr(OH)_2$ :

$M\left(\rm Sr(OH)_2\right) = 87.62 + 2\times (15.999 + 1.008) = 121.634\; \rm g \cdot mol^{-1}$ .

<h3>Number of moles of strontium hydroxide in the solution</h3>

$M\left(\rm Sr(OH)_2\right) =121.634\; \rm g \cdot mol^{-1}$ means that each mole of $\rm Sr(OH)_2$ formula units have a mass of $121.634\; \rm g$ .

The question states that there are $10.60\; \rm g$ of $\rm Sr(OH)_2$ in this solution.

How many moles of $\rm Sr(OH)_2$ formula units would that be?

$\begin{aligned}n\left(\rm Sr(OH)_2\right) &= \frac{m\left(\rm Sr(OH)_2\right)}{M\left(\rm Sr(OH)_2\right)}\\ &= \frac{10.60\; \rm g}{121.634\; \rm g \cdot mol^{-1}} \approx 8.71467\times 10^{-2}\; \rm mol\end{aligned}$ .

<h3>Molarity of this strontium hydroxide solution</h3>

There are $8.71467\times 10^{-2}\; \rm mol$ of $\rm Sr(OH)_2$ formula units in this $47\; \rm mL$ solution. Convert the unit of volume to liter:

$V = 47\; \rm mL = 0.047\; \rm L$ .

The molarity of a solution measures its molar concentration. For this solution:

$\begin{aligned}c\left(\rm Sr(OH)_2\right) &= \frac{n\left(\rm Sr(OH)_2\right)}{V}\\ &= \frac{8.71467\times 10^{-2}\; \rm mol}{0.047\; \rm L} \approx 1.854\; \rm mol \cdot L^{-1}\end{aligned}$ .

(Rounded to four significant figures.)

5 0

3 years ago

How do I solve this? please help and only respond with the answer/work. I will mark BRAINLIEST

Ulleksa [173]

Answer: I think the answer is 2.5 M.

Explanation: Formula: M = n/v

M= 10 mol / 4L

M= 2.5 M

4 0

2 years ago

Which of the following lists the correct symbol for the ion that tin forms when it loses 2 electrons, the correct classification

ser-zykov [4K]

Answer:

$\huge\boxed{\sf Option \ A}$

Explanation:

The symbol for TIN is Sn.

When Sn loses 2 electrons, it gets a double positive charge ( +2 ) and becomes $\sf Sn ^{+2}$ .

It becomes a cation.

The name of Ion is Tin ( II ) Ion.

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3>

6 0

3 years ago

Read 2 more answers

What is the energy required to go from a solid to a liquid called?

jek_recluse [69]

Answer:

C. The thermal energy of a substance.

Explanation:

Hope it helps.

3 0

3 years ago

Predict: In each "Climate type" box, Highlight the condition you think will lead to the fastest weathering for the given weather

yanalaym [24]

Answer:

Frost Wedging - Hot and dry

Clay Formation - Cold and Wet

Dissolving - Cold, and dry

Explanation:

The frost wedging happen when the climatic condition is hot and dry. The dry weather compensates the heat and the rock wedging happens quickly. For clay formation the weather has to be cold and wet. The cold weather will make the sand indulge with rock particles resulting in the clay formation.

6 0

2 years ago