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chubhunter [2.5K]
2 years ago
12

Select the most likely product for this reaction: upper a g upper n upper o subscript 3 (a q) plus upper n a upper o upper h (a

q) right arrow question mark. agoh(s) nano3(aq) ag2o(s) hno3(aq) ag(s) h2(g) o2(g)
Chemistry
2 answers:
Mamont248 [21]2 years ago
5 0

One of the most likely products for the reaction would be Ag_2O

<h3>Chemical reactions</h3>

The reaction between AgNO_3 and NaOH yields 3 products which are Ag_2O (a precipitate), NaNO_3, and H_2O as shown by the equation below:

2 AgNO_3 + 2 NaOH --- > Ag_2O + 2 NaNO_3 + H_2O

One of the products precipitates out of the solution to give the reaction a precipitation reaction look.

More on precipitation reaction can be found here: brainly.com/question/24158764

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pav-90 [236]2 years ago
3 0

The products of this reaction are  H2O + NaNO3 + Ag2O.

<h3>What is a reaction?</h3>

The term reaction has to do with the combination of two or more substances to yiled  product(s).

In this case, we have the reaction; AgNO3 + NaOH, the products of this reaction are  H2O + NaNO3 + Ag2O.

Learn more about reaction:brainly.com/question/17434463

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Calculate the mole fraction of kbr (molar mass 119.00 g/mol) in a solution made by dissolving 0.30 g kbr in 0.400 l of H2O (d =
julia-pushkina [17]

The mole fraction of KBr in the solution is 0.0001

<h3>How to determine the mole of water</h3>

We'll begin by calculating the mass of the water. This can be obtained as follow:

  • Volume of water = 0.4 L = 0.4 × 1000 = 400 mL
  • Density of water = 1 g/mL
  • Mass of water =?

Density = mass / volume

1 = Mass of water / 400

Croiss multiply

Mass of water = 1 × 400

Mass of water = 400 g

Finally, we shall determine the mole of the water

  • Mass of water = 400 g
  • Molar mass of water = 18.02 g/mol
  • Mole of water = ?

Mole = mass / molar mass

Mole of water = 400 / 18.02

Mole of water = 22.2 moles

<h3>How to de terminethe mole of KBr</h3>
  • Mass of KBr = 0.3 g
  • Molar mass of KBr = 119 g/mol
  • Mole of KBr = ?

Mole = mass / molar mass

Mole of KBr = 0.3 / 119

Mole of KBr = 0.0025 mole

<h3>How to determine the mole fraction of KBr</h3>
  • Mole of KBr = 0.0025 mole
  • Mole of water = 22.2 moles
  • Total mole = 0.0025 + 22.2 = 22.2025 moles
  • Mole fraction of KBr =?

Mole fraction = mole / total mole

Mole fraction of KBr = 0.0025 / 22.2025

Mole fraction of KBr = 0.0001

Learn more about mole fraction:

brainly.com/question/2769009

#SPJ1

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</span>An unstable nucleus contains a near excessive number of RNA chemical can spontaneously break apart into one or more nuclei all with a lighter  state. #believe
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