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VARVARA [1.3K]
3 years ago
11

Solve the equation 5* (3*7) * (65*70)

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0
3*7= 21 65*70= 4,550 5*21= 105*4,550=477,750
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In the sequence s of numbers, each term after the first two terms is the sum of the two immediately preceding terms. what is the
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Sn=n/2 (2a1 +(n-1)d)

[s5= 5/2 (2a1 +(5-1)d) = 5a1+10d]

s6=3(2a1+5d) = 6a1+15d
s4=2(2a1+3d) = 4a1+6d

6a1+15d -(4a1+6d) = 5 -----(1)

s7=7/2(2a1+6d) =7a1+21d

6a1+15d + 7a1+21d = 21 -----(2)

(1) 2a1+9d=5 -----(3)
(2) 13a1+36d=21 ----(4)

(3)*4 ; 8a1+36d=20 ----(5)
(4)-(5) 5a1 = 1
so a1 = 1/5

(3) 2a1+9d=5
2(1/5)+9d = 5
9d = 5-2/5 =23/5
d = 23/45


so [s5= 5/2 (2a1 +(5-1)d) = 5a1+10d = 5(1/5) + 10(23/45) = 1 + 5.11 = 6.11 ]

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