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3 years ago

Multiply (2a-5)(4a-7) Simplify your answer

Mathematics

2 answers:

Pie3 years ago

7 0

$(2a - 5)(4a - 7)$

$2a(4a - 7) - 5(4a - 7)$

$8 {a}^{2} - 14a - 20a + 35$

$8 {a}^{2} - 34a + 35$

FrozenT [24]3 years ago

5 0

Step-by-step explanation:

( 2a - 5 ) ( 4a - 7 )

2a ( 4a - 7) - 5 ( 4a - 7 )

8a² - 14a - 20a + 35

8a² -34a + 35

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For the binomial expansion of (x + y)^10, the value of k in the term 210x 6y k is a) 6 b) 4 c) 5 d) 7

Sloan [31]

Answer:

a) 6

Step-by-step explanation:

Expanding the polynomial using the formula:

$(x+y)^n=\sum_{k=0}^n \binom{n}{k} x^{n-k} y^k$

Also

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean $210x^6y^4$

We can deduce that this term will be located somewhere in the middle. So I will calculate $k= 5; k=6 \text{ and } k =7$ .

For $k=5$

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just $x^{n-k} y^k$

For $k=6$

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

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Which ordered pair is a solution of 2x – 3y = 6? A. (5, 1) B. (0, 6) C. (4, 3) D. (6, 2)

sergij07 [2.7K]

It’s D because 2x6 is 12 then 3x2 is 6 then 12-6=6

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Answer:

let cp be x

sp= 115x/100 ---(when 15%gain)

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