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Bess [88]
3 years ago
5

Please help me on 7&8 and please show your work :)

Mathematics
1 answer:
Llana [10]3 years ago
5 0
7. 6/12 or 1/2 | 8. 5/12

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What is the answer to this problem step by step (3+2)^2×7)-13+5^2?
Ainat [17]

Answer:

187

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

(3 + 2)² × 7 - 13 + 5²

<u>Step 2: Evaluate</u>

  1. (Parenthesis) Add:                     5² × 7 - 13 + 5²
  2. Exponents:                                 25 × 7 - 13 + 25
  3. Multiply:                                      175 - 13 + 25
  4. Subtract:                                     162 + 25
  5. Add:                                            187
5 0
3 years ago
Type the integer that makes the following addition sentence true: -5 + _ = -19
brilliants [131]

Answer:

-14

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
The diameters of a circle is 7m. Find its area to the nearest tenth?? Help please
Lady bird [3.3K]

Area =\pi r^{2}

The diameter is double the length of the radius

7 ÷ 2 = 3.5

3.5 × 3.5 = 12.25

12.25\pi = 38.4845100064751

38.4845100064751 rounded to the nearest tenth is 38.5

8 0
2 years ago
Read 2 more answers
Today, there were 2 members absent from the band. The present members folded 25 programs each, for a total of 525 programs. How
Dafna1 [17]

Answer:

23

Step-by-step explanation:

225/25 = 21

21+2=23

6 0
3 years ago
What is the radius of a sphere with a volume of 1/6 pie
Yakvenalex [24]

Answer:

\large\boxed{the\ radius\ R=\dfrac{1}{2}}

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

We have

V=\dfrac{1}{6}\pi

Substitute:

\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi        <em>divide both sides by π</em>

\dfrac{4}{3}R^3=\dfrac{1}{6}          <em>multiply both sides by 3</em>

3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}

4R^3=\dfrac{1}{2}          <em>divide both sides by 4</em>

R^3=\dfrac{1}{2}:4\\\\R^3=\dfrac{1}{2}\cdot\dfrac{1}{4}\\\\R^3=\dfrac{1}{8}\to R=\sqrt[3]{\dfrac{1}{8}}\\\\R=\dfrac{\sqrt1}{\sqrt8}\\\\R=\dfrac{1}{2}

3 0
3 years ago
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