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3 years ago

Which is M=9pm solved for p

Mathematics

1 answer:

zaharov [31]3 years ago

6 0

<h2>Answer:</h2>

<u>The value of </u><u>p :M/9m</u>

<h2>Explanation:</h2>

As we have been given value of M

Value of M=9pm

So we can find value of p from here by simple mathematics rule

M=9pm

divide both side with 9m so

M/9m=9pm/9m

we get value of p so M/9m=p.

we can write it as p=M/9m

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Car is moving on a circle on a plane. At time t (seconds), its x-coordinate is given by x(t) = 10 sin(200t + 3) + 30 while its y

Aleks [24]

Answer:

we have centre of circle as (30,40) and radius = 1

Step-by-step explanation:

Given that a car is moving on a circle on a plane.

At time t (seconds),

$x(t) = 10 sin(200t + 3) + 30$

and

$y(t) = 10 cos(200t + 3) + 40$

$x-30 = 10 sin(200t + 3) \\y-40 = 10 cos(200t + 3) + 40$

when we square and add both the equations we get

$(x-30)^2 + (y-40)^2 = 1$

(since sin square + cos square = 1 always)

i.e. we have centre of circle as (30,40) and radius = 1

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2 years ago

How do i convert from degrees to radians in terms of pi?

Alex787 [66]

Answer:

Formula

1° × π/180 = 0.01745rad

Step-by-step explanation:

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3 years ago

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11111nata11111 [884]

1 $\frac{1}{6}$

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3 years ago

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May someone please help?

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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the cir

FromTheMoon [43]

The statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Given the equation of circle be $x^{2} +y^{2}-2x-8=0$ .

We are required to find the appropriate statements related to the equation $x^{2} +y^{2}-2x-8=0$ .

$x^{2} +y^{2}-2x-8=0$ can be written as under:

$x^{2} +y^{2} -2x+1-9=0$

$x^{2} +1^{2}-2x+y^{2} -9=0$

$(x-1)^{2}+y^{2}$ -9=0

$(x-1)^{2} +y^{2} =9$

$(x-1)^{2}+y^{2} =3^{2}$

Equation of a circle usually in the form $x^{2} +y^{2} =a^{2}$ in which a is radius.

From the comparison of both the equations we get that radius is 3 units.

From the equation point will be (1,0). It is on the x axis.

Hence the statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Learn more about radius at brainly.com/question/24375372

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1 year ago