Answer:
<h2>11.02</h2>
Explanation:
Predict the frequency of a+b+c progeny = 11.02
Step by step Explanation for all genes
a---8%----b---------24%--------c
Double cross overs = (RF at first locus × RF at second locus)/100
= 8 × 24 /100 =1.92
Double cross over progeny;
a b+ c =0.96
a+ b c+= 0.96
single cross over progeny;
RF = 8
SCO at first locus progeny= 8 -DCO progeny= 8- 1.92 = 6.08
a b+ c+= 3.04
a+ b c= 3.04
single cross over at second locus progeny---
RF = 24
SCO at second locus progeny= 24-DCO progeny= 24 - 1.92 = 22.02
abc+= 11.02;
a+b+c = 11.02;
Total recombinants = 1.92 + 6.08 + 22.02 = 30.02
Total nonrecombinants are = 100 - 30.02 = 69.98
abc = 34.99
a+b+c+ = 34.99.
I honestly don’t know, I just need to answer this to ask a question ⚪️⚪️⚪️⚪️⚪️⚪️⚪️⚪️⚪️ ⚪️⚪️⚪️⚪️⚪️⚪️⚪️⚪️⚪️ ⚪️⚪️⚪️⚪️⚪️⚪️⚪️⚪️⚪️
Answer:
d. 3/8
Explanation:
Black coat color (B) is dominant over red coat color (b) and solid color (S) is dominant over spotted color (b).
BbSs was crossed with Bbss
BbSs x Bbss
Offspring:
<em>2 BBSs black, solid</em>
<em>2 BBss black, spotted</em>
<em>4 BbSs black solid</em>
<em>4 Bbss black, spotted</em>
<em>2 bbSs red, solid</em>
<em>2 bbss red spotted</em>
Total black solid = 6
Hence, the chance that black solid individual would be produced = 6/16 = 3/8.
The correct option is d.
<em>See the attached for the Punnet's square analysis.</em>
Answer:
b, this is because a consumer, is something that consumes something, and the clam consumes the energy and nutrients when it filters the particles in from the water. Because it consumes these, it is a consumer for that reason. So, the answer is b. Hope this helps!!!
<span>It is called the fimbriae.</span>