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3 years ago

How many no real complex roots does the polynomial f (x) = x^4 - x^2- 12 have?

Mathematics

1 answer:

asambeis [7]3 years ago

6 0

<h3>Answer:</h3>

2 real roots
2 complex roots

<h3>Step-by-step explanation:</h3>

f(x) factors as ...

... f(x) = (x² -4)(x² +3) = (x -2)(x +2)(x² +3)

The real roots are x = ±2.

The complex roots are x = ±i√3.

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We don't know what "no real complex roots" means. We suspect your answer may be C. 2.

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Answer:

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So the answer for this case would be n=5 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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Solution to the problem

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$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The margin of error is given by this formula:

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We can use as estimator for the population deviation the sample deviation $\hat \sigma = s$

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$n=(\frac{1.640(2.5)}{2})^2 =4.2 \approx 5$

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