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Ipatiy [6.2K]
3 years ago
7

There are two types of ice cream cones - strawberry and peach. You and 24 of your closest friends are going to buy ice cream con

es. If 15 people buy strawberry cones and 20 people buy peach cones, how many people bought both strawberry and peach cones?
Mathematics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

10 people bought both strawberry and peach cones

Step-by-step explanation:

Given that there are two types of ice cream cones - strawberry and peach. You and 24 of your closest friends are going to buy ice cream cones.

Assuming that each one had atleast one ice cream we get

n(AUB) =24+1 =25

A - no of people bought straw berry

B - no of people bought peach cones

n(A) = 15 and n(B) =20

Hence we have

n(AUB)=n(A)+n(B)-n(AB)\\25= 15+20-n(AB)\\n(AB) = 10

10 people bought both strawberry and peach cones

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The population of a certain town was 10,000 in 1990. The rate of change of the population, measured in people per year, is model
Katena32 [7]

The question is incomplete. The complete question is :

The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?

Solution :

According to the question,

The rate of change of population is given as :

$\frac{dP(t)}{dt}=200e^{0.02t}$  in 1990.

Now integrating,

$\int_0^{20}\frac{dP(t)}{dt}dt=\int_0^{20}200e^{0.02t} \ dt$

                    $=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$

                   $=10,000[e^{0.4}-1]$

                    $=10,000[0.49]$

                    =4900

$\frac{dP(t)}{dt}=200e^{0.02t}$

$\int1.dP(t)=200e^{0.02t}dt$

$P=\frac{200}{0.02}e^{0.02t}$

$P=10,000e^{0.02t}$

$P=P_0e^{kt}$

This is initial population.

k is change in population.

So in 1995,

$P=P_0e^{kt}$

   $=10,000e^{0.02(5)}$

   $=11051$

In 2000,

$P=10,000e^{0.02(10)}$

   =12,214

Therefore, the change in the population between 1995 and 2000 = 1,163.

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Hey mate
here is your answer

length and width are given in the ratio are ;(4:7)
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4x×7x=700
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Solve by Elimination: <br> x + 6y = 28<br> 2x - 3y = -19
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Answer:

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Step-by-step explanation:

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(substitute the value of x)

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Chicken wings, chicken tenders or chicken nuggets
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