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trapecia [35]
3 years ago
7

Divide. Each one. Please show work!! Thank you!! Please help. I don’t know how

Mathematics
2 answers:
Bas_tet [7]3 years ago
8 0
Just use Photomath it helps a lot
Greeley [361]3 years ago
5 0
Yeah I agree use photomath , and it shows the work too
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The double number line shows the amount of time a hen needs to lay 1 egg.
Scorpion4ik [409]

I realize the double number line in this exercise can be as shown in the attached image, in that case, the table, correctly completed is:

Eggs      Time (hours)

 3                   <u>75</u>

 <u>4</u>                  100

 12                <u>300</u>

Method to complete the table.

First, you must see the double number line (attached image), in this we identify a hen needs 25 hours to lay 1 egg, by this reason, to identify the time required for a certain number of eggs, just multiply the number of eggs by 25 (the number of hours shown on the double number line), then:

  • 3 * 25 = <u>75</u>
  • 12 * 25 = <u>300</u>

To calculate the number of eggs taking into account the time, you must divide the hours by 25:

  • 100 / 25 = <u>4</u>

In this way, <u><em>you can check that the answers are 75, 4, and 300 respectively, to complete the table in the correct form</em></u>.

You can review more exercises and test your new knowledge about the double number line at the following link: brainly.com/question/13553589?referrer=searchResults

8 0
3 years ago
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
WILL GIVE BRAINLST <br><br> HAVE A AMAZING DAy !!
MissTica

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Which of the following equations belongs to an ellipse with vertical orientation?
Mekhanik [1.2K]

Answer:

d. 16x² + y² = 16

Step-by-step explanation:

Standard form of an ellipse is:

x² / a² + y² / b² = 1

If b > a, the ellipse has a vertical orientation.

We can ignore options b and c, since they have minus signs in them.

Convert the other options to standard form:

a. x² / (1/16) + y² / (1/25) = 1

x² / (1/4)² + y² / (1/5)² = 1

1/4 > 1/5

d. x² + y² / 16 = 1

x² / 1² + y² / 4² = 1

1 < 4

e. x² / 16 + y² = 1

x² / 4² + y² / 1² = 1

4 > 1

Of these three options, only d is a vertical ellipse.

6 0
3 years ago
Read 2 more answers
Find the area of this triangle, round to the nearest 10th
Juliette [100K]

Answer:

109.3 yard²

Step-by-step explanation:

Area of triangle = bh / 2

base is 23yd

height is 9.5yd

bh / 2 = 23 × 9.5 / 2

Area = 218.5 / 2

Area = 109.25 yd²; rounded to the nearest tenth is 109.3yd²

7 0
2 years ago
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