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Len [333]
3 years ago
9

The study of matter and chemical reactions in the body is known as

Biology
1 answer:
pychu [463]3 years ago
7 0
That would be biochemistry. 
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What is globle warming
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Answer:

a gradual increase in the overall temperature of the earth's atmosphere generally attributed to the greenhouse effect caused by increased levels of carbon dioxide, chlorofluorocarbons, and other pollutants.

Explanation:

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A nurse is caring for a client who has cancer. the clien has decided to stop treatment and requests a refferal to hospice
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When does fetal erythrocyte production shift from the liver to the bone marrow?
vichka [17]

Answer: After seven months.

Explanation:

The blood carries various substances that must be transported from one part of the body to another. Red blood cells are an important component of the blood because their function is to carry oxygen to the body tissues and exchange it for carbon dioxide, which is carried and removed by the lungs.

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6 0
3 years ago
Assume that you have 1 mL of a solution of amylase (an enzyme) at a concentration of 15 mg protein/mL. Calculate the volume of d
lidiya [134]

Answer:

42,5 mL

Explanation:

We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.

DF=\frac{Vi}{Vf}

<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>

The first step is to have the same measurment unit so we need to convert 345 µg to mg.

we know that 1 µg equals 0,001 g, hence:

345 µg = 0,345 mg

now the final volume is 0,345 mg  protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula

DF= \frac{15mg protein/mL}{0.345mg protein/mL}

DF= 43,5 mg protein/ mL

Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL

43,5mL-1,0mL = 42,5 mL

So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)

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